detailed information: The input equation set is:
 | | | | | | | 64 | A | + | | 16 | B | + | | 4 | C | + | | D | = | | 2 | | (3) |
| | | 125 | A | + | | 25 | B | + | | 5 | C | + | | D | = | | - | 3 2 | | (4) |
| Question solving process:
Add both sides of equation (1) to both sides of equation (2) ,the equations are reduced to:
 | | | | | | | 64 | A | + | | 16 | B | + | | 4 | C | + | | D | = | | 2 | | (3) |
| | | 125 | A | + | | 25 | B | + | | 5 | C | + | | D | = | | - | 3 2 | | (4) |
|
Multiply both sides of equation (1) by 8, the equation can be obtained: | | -64 | A | + | | 32 | B | | -16 | C | + | | 8 | D | = | | 32 | (5) | , then add the two sides of equation (5) to both sides of equation (3), the equations are reduced to:
 | | | | | | | | 125 | A | + | | 25 | B | + | | 5 | C | + | | D | = | | - | 3 2 | | (4) |
|
Multiply both sides of equation (1) by 125 Divide the two sides of equation (1) by 8, the equation can be obtained: | | -125 | A | + | | | 125 2 | B | | - | 125 4 | C | + | | | 125 8 | D | = | | | 125 2 | (6) | , then add the two sides of equation (6) to both sides of equation (4), the equations are reduced to:
 | | | | | | | | | 175 2 | B | | - | 105 4 | C | + | | | 133 8 | D | = | | 61 | | (4) |
|
Multiply both sides of equation (2) by 6, the equation can be obtained: , then subtract both sides of equation (7) from both sides of equation (3), the equations are reduced to:
 | | | | | | | | | 175 2 | B | | - | 105 4 | C | + | | | 133 8 | D | = | | 61 | | (4) |
|
Multiply both sides of equation (2) by 175 Divide the two sides of equation (2) by 16, the equation can be obtained: , then subtract both sides of equation (8) from both sides of equation (4), the equations are reduced to:
 | | | | | | | - | 105 4 | C | | - | 21 4 | D | = | | - | 37 8 | | (4) |
|
Multiply both sides of equation (3) by 35 Divide the two sides of equation (3) by 16, the equation can be obtained: | | - | 105 4 | C | | - | 105 16 | D | = | | - | 35 8 | (9) | , then subtract both sides of equation (9) from both sides of equation (4), the equations are reduced to:
Multiply both sides of equation (4) by 16 Divide both sides of equation (4) by 7, get the equation:, then add the two sides of equation (10) to both sides of equation (3), get the equation:
Multiply both sides of equation (4) by 32 Divide both sides of equation (4) by 21, get the equation:, then subtract both sides of equation (11) from both sides of equation (2), get the equation:
Multiply both sides of equation (4) by 16 Divide both sides of equation (4) by 21, get the equation:, then subtract both sides of equation (12) from both sides of equation (1), get the equation:
Divide both sides of equation (3) by 6, get the equation:, then subtract both sides of equation (13) from both sides of equation (1), get the equation:
Divide both sides of equation (2) by 2, get the equation:, then subtract both sides of equation (14) from both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |