detailed information: The input equation set is:
 | | | | | | -2 | B | + | | 3 | C | + | | 10 | D | | -3 | E | + | | 2 | F | = | | 0 | | (4) |
| | | Question solving process:
交After the exchange of equation (1) and equation (2), the equation system becomes:
 | | | | | | -2 | B | + | | 3 | C | + | | 10 | D | | -3 | E | + | | 2 | F | = | | 0 | | (4) |
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Add both sides of equation (1) to both sides of equation (3) ,the equations are reduced to:
 | | | | | | -2 | B | + | | 3 | C | + | | 10 | D | | -3 | E | + | | 2 | F | = | | 0 | | (4) |
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Add both sides of equation (2) to both sides of equation (3) ,the equations are reduced to:
 | | | | | | -2 | B | + | | 3 | C | + | | 10 | D | | -3 | E | + | | 2 | F | = | | 0 | | (4) |
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Multiply both sides of equation (2) by 2, the equation can be obtained: , then subtract both sides of equation (7) from both sides of equation (4), the equations are reduced to:
Add both sides of equation (2) to both sides of equation (6) ,the equations are reduced to:
Multiply both sides of equation (3) by 3 Divide the two sides of equation (3) by 7, the equation can be obtained: , then add the two sides of equation (8) to both sides of equation (4), the equations are reduced to:
Multiply both sides of equation (3) by 3 Divide the two sides of equation (3) by 7, the equation can be obtained: , then add the two sides of equation (9) to both sides of equation (5), the equations are reduced to:
Multiply both sides of equation (4) by 31 Divide the two sides of equation (4) by 25, the equation can be obtained: | | | 62 7 | D | | - | 93 25 | E | + | | | 62 25 | F | = | | | 93 175 | (10) | , then add the two sides of equation (10) to both sides of equation (5), the equations are reduced to:
 | | | | | | | - | 18 25 | E | + | | | 12 25 | F | = | | | 24 25 | | (5) |
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Multiply both sides of equation (4) by 7 Divide the two sides of equation (4) by 50, the equation can be obtained: | | D | | - | 21 50 | E | + | | | 7 25 | F | = | | | 3 50 | (11) | , then subtract both sides of equation (11) from both sides of equation (6), the equations are reduced to:
 | | | | | | | - | 18 25 | E | + | | | 12 25 | F | = | | | 24 25 | | (5) |
| | | 121 50 | E | | - | 7 25 | F | = | | - | 3 50 | | (6) |
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Multiply both sides of equation (5) by 121 Divide the two sides of equation (5) by 36, the equation can be obtained: | - | 121 50 | E | + | | | 121 75 | F | = | | | 242 75 | (12) | , then add the two sides of equation (12) to both sides of equation (6), the equations are reduced to:
 | | | | | | | - | 18 25 | E | + | | | 12 25 | F | = | | | 24 25 | | (5) |
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Multiply both sides of equation (6) by 9 Divide both sides of equation (6) by 25, get the equation:, then subtract both sides of equation (13) from both sides of equation (5), get the equation:
Multiply both sides of equation (6) by 3 Divide both sides of equation (6) by 2, get the equation:, then subtract both sides of equation (14) from both sides of equation (4), get the equation:
Multiply both sides of equation (5) by 25 Divide both sides of equation (5) by 6, get the equation:, then subtract both sides of equation (15) from both sides of equation (4), get the equation:
Multiply both sides of equation (4) by 7 Divide both sides of equation (4) by 25, get the equation:, then add the two sides of equation (16) to both sides of equation (3), get the equation:
Multiply both sides of equation (4) by 7 Divide both sides of equation (4) by 50, get the equation:, then subtract both sides of equation (17) from both sides of equation (2), get the equation:
Divide both sides of equation (3) by 7, get the equation:, then add the two sides of equation (18) to both sides of equation (1), get the equation:
Multiply both sides of equation (2) by 2, get the equation:, then subtract both sides of equation (19) from both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |