detailed information: The input equation set is:
 | | | | A | + | | | 4 5 | B | + | | | 16 25 | C | + | | | 51 100 | D | = | | | 35 2 | | (1) |
| | A | + | | | 1 2 | B | + | | | 1 2 | C | + | | | 1 2 | D | = | | | 41 2 | | (2) |
| | A | + | | | 3 2 | B | + | | | 3 2 | C | + | | | 3 2 | D | = | | | 47 2 | | (3) |
| | A | + | | | 3 2 | B | + | | | 3 2 | C | + | | | 3 2 | D | = | | | 53 2 | | (4) |
| Question solving process:
Subtract both sides of equation (1) from both sides of equation (2) ,the equations are reduced to:
 | | | | A | + | | | 4 5 | B | + | | | 16 25 | C | + | | | 51 100 | D | = | | | 35 2 | | (1) |
| - | 3 10 | B | | - | 7 50 | C | | - | 1 100 | D | = | | 3 | | (2) |
| | A | + | | | 3 2 | B | + | | | 3 2 | C | + | | | 3 2 | D | = | | | 47 2 | | (3) |
| | A | + | | | 3 2 | B | + | | | 3 2 | C | + | | | 3 2 | D | = | | | 53 2 | | (4) |
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Subtract both sides of equation (1) from both sides of equation (3) ,the equations are reduced to:
 | | | | A | + | | | 4 5 | B | + | | | 16 25 | C | + | | | 51 100 | D | = | | | 35 2 | | (1) |
| - | 3 10 | B | | - | 7 50 | C | | - | 1 100 | D | = | | 3 | | (2) |
| | | 7 10 | B | + | | | 43 50 | C | + | | | 99 100 | D | = | | 6 | | (3) |
| | A | + | | | 3 2 | B | + | | | 3 2 | C | + | | | 3 2 | D | = | | | 53 2 | | (4) |
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Subtract both sides of equation (1) from both sides of equation (4) ,the equations are reduced to:
 | | | | A | + | | | 4 5 | B | + | | | 16 25 | C | + | | | 51 100 | D | = | | | 35 2 | | (1) |
| - | 3 10 | B | | - | 7 50 | C | | - | 1 100 | D | = | | 3 | | (2) |
| | | 7 10 | B | + | | | 43 50 | C | + | | | 99 100 | D | = | | 6 | | (3) |
| | | 7 10 | B | + | | | 43 50 | C | + | | | 99 100 | D | = | | 9 | | (4) |
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Multiply both sides of equation (2) by 7 Divide the two sides of equation (2) by 3, the equation can be obtained: | - | 7 10 | B | | - | 49 150 | C | | - | 7 300 | D | = | | 7 | (5) | , then add the two sides of equation (5) to both sides of equation (3), the equations are reduced to:
 | | | | A | + | | | 4 5 | B | + | | | 16 25 | C | + | | | 51 100 | D | = | | | 35 2 | | (1) |
| - | 3 10 | B | | - | 7 50 | C | | - | 1 100 | D | = | | 3 | | (2) |
| | | | 7 10 | B | + | | | 43 50 | C | + | | | 99 100 | D | = | | 9 | | (4) |
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Multiply both sides of equation (2) by 7 Divide the two sides of equation (2) by 3, the equation can be obtained: | - | 7 10 | B | | - | 49 150 | C | | - | 7 300 | D | = | | 7 | (6) | , then add the two sides of equation (6) to both sides of equation (4), the equations are reduced to:
 | | | | A | + | | | 4 5 | B | + | | | 16 25 | C | + | | | 51 100 | D | = | | | 35 2 | | (1) |
| - | 3 10 | B | | - | 7 50 | C | | - | 1 100 | D | = | | 3 | | (2) |
| | |
Subtract both sides of equation (3) from both sides of equation (4) ,the equations are reduced to:
 | | | | A | + | | | 4 5 | B | + | | | 16 25 | C | + | | | 51 100 | D | = | | | 35 2 | | (1) |
| - | 3 10 | B | | - | 7 50 | C | | - | 1 100 | D | = | | 3 | | (2) |
| | |
由第(4)方程式可以看出,该方程组无解。
解方程组的详细方法请参阅:《多元一次方程组的解法》 |