detailed information: The input equation set is:
 | | | | A | + | | B | + | | C | + | | D | + | | E | = | | 53 | | (1) |
| | 15000 | A | + | | 11000 | B | + | | 7600 | C | + | | 5000 | D | + | | 2000 | E | = | | 200000 | | (2) |
| | | | Question solving process:
Multiply both sides of equation (1) by 15000, the equation can be obtained: | | 15000 | A | + | | 15000 | B | + | | 15000 | C | + | | 15000 | D | + | | 15000 | E | = | | 795000 | (6) | , then subtract both sides of equation (6) from both sides of equation (2), the equations are reduced to:
 | | | | A | + | | B | + | | C | + | | D | + | | E | = | | 53 | | (1) |
| -4000 | B | | -7400 | C | | -10000 | D | | -13000 | E | = | | -595000 | | (2) |
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Divide both sides of equation (2) by 4000, get the equation: | -1 | B | | - | 37 20 | C | | - | 5 2 | D | | - | 13 4 | E | = | | - | 595 4 | (7) | , then add the two sides of equation (7) to both sides of equation (1), get the equation:
 | | | | A | | - | 17 20 | C | | - | 3 2 | D | | - | 9 4 | E | = | | - | 383 4 | | (1) |
| -4000 | B | | -7400 | C | | -10000 | D | | -13000 | E | = | | -595000 | | (2) |
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The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
 | | | | A | | - | 17 20 | C | | - | 3 2 | D | | - | 9 4 | E | = | | - | 383 4 | | (1) |
| | B | + | | | 37 20 | C | + | | | 5 2 | D | + | | | 13 4 | E | = | | | 595 4 | | (2) |
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Therefore, the solution of the equation set is:
 | | | A = | | - | 383 4 | + | | | 17 20 | C | + | | | 3 2 | D | + | | | 9 4 | E |
| B = | | | 595 4 | - | | | 37 20 | C | - | | | 5 2 | D | - | | | 13 4 | E |
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Convert the solution of the equation set to decimals:
 | | | A = | | -95.750000 | + | | | 17 20 | C | + | | | 3 2 | D | + | | | 9 4 | E |
| B = | | 148.750000 | - | | | 37 20 | C | - | | | 5 2 | D | - | | | 13 4 | E |
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Where: C, D, E are arbitrary constants. 解方程组的详细方法请参阅:《多元一次方程组的解法》 |