detailed information: The input equation set is:
| | | | | | | | 4 | A | + | | 4 | C | + | | 4 | D | + | | 4 | E | = | | 7 | | (5) |
| | Question solving process:
Subtract both sides of equation (1) from both sides of equation (4) ,the equations are reduced to:
| | | | | | | | 4 | A | + | | 4 | C | + | | 4 | D | + | | 4 | E | = | | 7 | | (5) |
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Subtract both sides of equation (1) from both sides of equation (5) ,the equations are reduced to:
Multiply both sides of equation (2) by 2, the equation can be obtained: , then subtract both sides of equation (7) from both sides of equation (4), the equations are reduced to:
Multiply both sides of equation (2) by 2, the equation can be obtained: , then add the two sides of equation (8) to both sides of equation (6), the equations are reduced to:
| | | | | | | | -4 | C | | -4 | D | | -4 | E | | -8 | F | = | | -16 | | (6) |
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Subtract both sides of equation (3) from both sides of equation (5) ,the equations are reduced to:
| | | | | | | | -4 | C | | -4 | D | | -4 | E | | -8 | F | = | | -16 | | (6) |
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Add both sides of equation (3) to both sides of equation (6) ,the equations are reduced to:
交After the exchange of equation (4) and equation (5), the equation system becomes:
Add both sides of equation (5) to both sides of equation (6) ,the equations are reduced to:
Add both sides of equation (5) to both sides of equation (2), get the equation:
Subtract both sides of equation (5) from both sides of equation (1), get the equation:
Subtract both sides of equation (4) from both sides of equation (3), get the equation:
Add both sides of equation (4) to both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
Where: F are arbitrary constants. 解方程组的详细方法请参阅:《多元一次方程组的解法》 |