detailed information: The input equation set is:
| | | | -25 | A | + | | 85 | B | | -50 | C | = | | 230 | | (2) |
| | | | 33 10 | A | | - | 43 10 | B | + | | C | = | | 0 | | (4) |
| Question solving process:
Multiply both sides of equation (1) by 5 Divide the two sides of equation (1) by 7, the equation can be obtained: | | 25 | A | | - | 125 7 | B | | - | 5 7 | D | = | | 0 | (5) | , then add the two sides of equation (5) to both sides of equation (2), the equations are reduced to:
| | | | | | 470 7 | B | | -50 | C | | - | 5 7 | D | = | | 230 | | (2) |
| | | | 33 10 | A | | - | 43 10 | B | + | | C | = | | 0 | | (4) |
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Multiply both sides of equation (1) by 33 Divide the two sides of equation (1) by 350, the equation can be obtained: | | | 33 10 | A | | - | 33 14 | B | | - | 33 350 | D | = | | 0 | (6) | , then subtract both sides of equation (6) from both sides of equation (4), the equations are reduced to:
| | | | | | 470 7 | B | | -50 | C | | - | 5 7 | D | = | | 230 | | (2) |
| | - | 68 35 | B | + | | C | + | | | 33 350 | D | = | | 0 | | (4) |
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Multiply both sides of equation (2) by 35 Divide the two sides of equation (2) by 47, the equation can be obtained: | | 50 | B | | - | 1750 47 | C | | - | 25 47 | D | = | | | 8050 47 | (7) | , then add the two sides of equation (7) to both sides of equation (3), the equations are reduced to:
| | | | | | 470 7 | B | | -50 | C | | - | 5 7 | D | = | | 230 | | (2) |
| | | 5300 47 | C | + | | | 22 47 | D | = | | | 8050 47 | | (3) |
| - | 68 35 | B | + | | C | + | | | 33 350 | D | = | | 0 | | (4) |
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Multiply both sides of equation (2) by 34 Divide the two sides of equation (2) by 1175, the equation can be obtained: | | | 68 35 | B | | - | 68 47 | C | | - | 34 1645 | D | = | | | 1564 235 | (8) | , then add the two sides of equation (8) to both sides of equation (4), the equations are reduced to:
| | | | | | 470 7 | B | | -50 | C | | - | 5 7 | D | = | | 230 | | (2) |
| | | 5300 47 | C | + | | | 22 47 | D | = | | | 8050 47 | | (3) |
| - | 21 47 | C | + | | | 173 2350 | D | = | | | 1564 235 | | (4) |
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Multiply both sides of equation (3) by 21 Divide the two sides of equation (3) by 5300, the equation can be obtained: | | | 21 47 | C | + | | | 231 124550 | D | = | | | 3381 4982 | (9) | , then add the two sides of equation (9) to both sides of equation (4), the equations are reduced to:
| | | | | | 470 7 | B | | -50 | C | | - | 5 7 | D | = | | 230 | | (2) |
| | | 5300 47 | C | + | | | 22 47 | D | = | | | 8050 47 | | (3) |
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Multiply both sides of equation (4) by 583 Divide both sides of equation (4) by 94, get the equation: | | | 1166 2491 | D | = | | | 42757 940 | (10) | , then subtract both sides of equation (10) from both sides of equation (3), get the equation:
| | | | | | 470 7 | B | | -50 | C | | - | 5 7 | D | = | | 230 | | (2) |
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Multiply both sides of equation (4) by 12455 Divide both sides of equation (4) by 1316, get the equation:, then add the two sides of equation (11) to both sides of equation (2), get the equation:
Multiply both sides of equation (4) by 2491 Divide both sides of equation (4) by 188, get the equation:, then add the two sides of equation (12) to both sides of equation (1), get the equation:
| | | | 35 | A | | -25 | B | = | | | 206011 2120 | | (1) |
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Multiply both sides of equation (3) by 47 Divide both sides of equation (3) by 106, get the equation:, then add the two sides of equation (13) to both sides of equation (2), get the equation:
| | | | 35 | A | | -25 | B | = | | | 206011 2120 | | (1) |
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Multiply both sides of equation (2) by 35 Divide both sides of equation (2) by 94, get the equation:, then add the two sides of equation (14) to both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |