detailed information: The input equation set is:
| | | | A | + | | B | + | | C | + | | D | + | | 2 | E | = | | 6 | | (1) |
| | A | + | | B | + | | C | + | | 2 | D | + | | E | = | | 12 | | (2) |
| | A | + | | B | + | | 2 | C | + | | D | + | | E | = | | 24 | | (3) |
| | A | + | | 2 | B | + | | C | + | | D | + | | E | = | | 48 | | (4) |
| | 2 | A | + | | B | + | | C | + | | D | + | | E | = | | 96 | | (5) |
| Question solving process:
Subtract both sides of equation (1) from both sides of equation (2) ,the equations are reduced to:
| | | | A | + | | B | + | | C | + | | D | + | | 2 | E | = | | 6 | | (1) |
| | | A | + | | B | + | | 2 | C | + | | D | + | | E | = | | 24 | | (3) |
| | A | + | | 2 | B | + | | C | + | | D | + | | E | = | | 48 | | (4) |
| | 2 | A | + | | B | + | | C | + | | D | + | | E | = | | 96 | | (5) |
|
Subtract both sides of equation (1) from both sides of equation (3) ,the equations are reduced to:
| | | | A | + | | B | + | | C | + | | D | + | | 2 | E | = | | 6 | | (1) |
| | | | A | + | | 2 | B | + | | C | + | | D | + | | E | = | | 48 | | (4) |
| | 2 | A | + | | B | + | | C | + | | D | + | | E | = | | 96 | | (5) |
|
Subtract both sides of equation (1) from both sides of equation (4) ,the equations are reduced to:
| | | | A | + | | B | + | | C | + | | D | + | | 2 | E | = | | 6 | | (1) |
| | | | | 2 | A | + | | B | + | | C | + | | D | + | | E | = | | 96 | | (5) |
|
Multiply both sides of equation (1) by 2, the equation can be obtained: | | 2 | A | + | | 2 | B | + | | 2 | C | + | | 2 | D | + | | 4 | E | = | | 12 | (6) | , then subtract both sides of equation (6) from both sides of equation (5), the equations are reduced to:
| | | | A | + | | B | + | | C | + | | D | + | | 2 | E | = | | 6 | | (1) |
| | | | |
交After the exchange of equation (2) and equation (4), the equation system becomes:
| | | | A | + | | B | + | | C | + | | D | + | | 2 | E | = | | 6 | | (1) |
| | | | |
Add both sides of equation (2) to both sides of equation (5) ,the equations are reduced to:
| | | | A | + | | B | + | | C | + | | D | + | | 2 | E | = | | 6 | | (1) |
| | | | |
Add both sides of equation (3) to both sides of equation (5) ,the equations are reduced to:
| | | | A | + | | B | + | | C | + | | D | + | | 2 | E | = | | 6 | | (1) |
| | | | |
Add both sides of equation (4) to both sides of equation (5) ,the equations are reduced to:
| | | | A | + | | B | + | | C | + | | D | + | | 2 | E | = | | 6 | | (1) |
| | | | |
Divide both sides of equation (5) by 6, get the equation:, then subtract both sides of equation (7) from both sides of equation (4), get the equation:
| | | | A | + | | B | + | | C | + | | D | + | | 2 | E | = | | 6 | | (1) |
| | | | |
Divide both sides of equation (5) by 6, get the equation:, then subtract both sides of equation (8) from both sides of equation (3), get the equation:
| | | | A | + | | B | + | | C | + | | D | + | | 2 | E | = | | 6 | | (1) |
| | | | |
Divide both sides of equation (5) by 6, get the equation:, then subtract both sides of equation (9) from both sides of equation (2), get the equation:
| | | | A | + | | B | + | | C | + | | D | + | | 2 | E | = | | 6 | | (1) |
| | | | |
Divide both sides of equation (5) by 3, get the equation:, then add the two sides of equation (10) to both sides of equation (1), get the equation:
Subtract both sides of equation (4) from both sides of equation (1), get the equation:
Subtract both sides of equation (3) from both sides of equation (1), get the equation:
Subtract both sides of equation (2) from both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |