detailed information: The input equation set is:
| | | | 2 | A | + | | 14 | B | + | | C | + | | 93 | E | = | | 78 | | (1) |
| | 2 | A | + | | 15 | B | + | | 2 | C | + | | D | + | | 88 | E | = | | 77 | | (2) |
| | | A | + | | 6 | B | + | | 3 | C | + | | 67 | E | = | | 38 | | (4) |
| | 3 | A | + | | 11 | B | + | | C | + | | 92 | E | = | | 78 | | (5) |
| Question solving process:
Subtract both sides of equation (1) from both sides of equation (2) ,the equations are reduced to:
| | | | 2 | A | + | | 14 | B | + | | C | + | | 93 | E | = | | 78 | | (1) |
| | | | A | + | | 6 | B | + | | 3 | C | + | | 67 | E | = | | 38 | | (4) |
| | 3 | A | + | | 11 | B | + | | C | + | | 92 | E | = | | 78 | | (5) |
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Divide the two sides of equation (1) by 2, the equation can be obtained: | | A | + | | 7 | B | + | | | 1 2 | C | + | | | 93 2 | E | = | | 39 | (6) | , then subtract both sides of equation (6) from both sides of equation (4), the equations are reduced to:
| | | | 2 | A | + | | 14 | B | + | | C | + | | 93 | E | = | | 78 | | (1) |
| | | -1 | B | + | | | 5 2 | C | + | | | 41 2 | E | = | | -1 | | (4) |
| | 3 | A | + | | 11 | B | + | | C | + | | 92 | E | = | | 78 | | (5) |
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Multiply both sides of equation (1) by 3 Divide the two sides of equation (1) by 2, the equation can be obtained: | | 3 | A | + | | 21 | B | + | | | 3 2 | C | + | | | 279 2 | E | = | | 117 | (7) | , then subtract both sides of equation (7) from both sides of equation (5), the equations are reduced to:
| | | | 2 | A | + | | 14 | B | + | | C | + | | 93 | E | = | | 78 | | (1) |
| | | -1 | B | + | | | 5 2 | C | + | | | 41 2 | E | = | | -1 | | (4) |
| -10 | B | | - | 1 2 | C | | - | 95 2 | E | = | | -39 | | (5) |
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Add both sides of equation (2) to both sides of equation (4) ,the equations are reduced to:
| | | | 2 | A | + | | 14 | B | + | | C | + | | 93 | E | = | | 78 | | (1) |
| | | | -10 | B | | - | 1 2 | C | | - | 95 2 | E | = | | -39 | | (5) |
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Multiply both sides of equation (2) by 10, the equation can be obtained: | | 10 | B | + | | 10 | C | + | | 10 | D | | -50 | E | = | | -10 | (8) | , then add the two sides of equation (8) to both sides of equation (5), the equations are reduced to:
| | | | 2 | A | + | | 14 | B | + | | C | + | | 93 | E | = | | 78 | | (1) |
| | | | | | 19 2 | C | + | | 10 | D | | - | 195 2 | E | = | | -49 | | (5) |
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交After the exchange of equation (3) and equation (4), the equation system becomes:
| | | | 2 | A | + | | 14 | B | + | | C | + | | 93 | E | = | | 78 | | (1) |
| | | | | | 19 2 | C | + | | 10 | D | | - | 195 2 | E | = | | -49 | | (5) |
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Multiply both sides of equation (3) by 19 Divide the two sides of equation (3) by 7, the equation can be obtained: | | | 19 2 | C | + | | | 19 7 | D | + | | | 589 14 | E | = | | - | 38 7 | (9) | , then subtract both sides of equation (9) from both sides of equation (5), the equations are reduced to:
| | | | 2 | A | + | | 14 | B | + | | C | + | | 93 | E | = | | 78 | | (1) |
| | | | | | 51 7 | D | | - | 977 7 | E | = | | - | 305 7 | | (5) |
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交After the exchange of equation (4) and equation (5), the equation system becomes:
| | | | 2 | A | + | | 14 | B | + | | C | + | | 93 | E | = | | 78 | | (1) |
| | | | | 51 7 | D | | - | 977 7 | E | = | | - | 305 7 | | (4) |
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Multiply both sides of equation (4) by 7 Divide both sides of equation (4) by 51, get the equation: | | D | | - | 977 51 | E | = | | - | 305 51 | (10) | , then subtract both sides of equation (10) from both sides of equation (3), get the equation:
| | | | 2 | A | + | | 14 | B | + | | C | + | | 93 | E | = | | 78 | | (1) |
| | | | 7 2 | C | + | | | 3535 102 | E | = | | | 203 51 | | (3) |
| | | 51 7 | D | | - | 977 7 | E | = | | - | 305 7 | | (4) |
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Multiply both sides of equation (4) by 7 Divide both sides of equation (4) by 51, get the equation: | | D | | - | 977 51 | E | = | | - | 305 51 | (11) | , then subtract both sides of equation (11) from both sides of equation (2), get the equation:
| | | | 2 | A | + | | 14 | B | + | | C | + | | 93 | E | = | | 78 | | (1) |
| | B | + | | C | + | | | 722 51 | E | = | | | 254 51 | | (2) |
| | | 7 2 | C | + | | | 3535 102 | E | = | | | 203 51 | | (3) |
| | | 51 7 | D | | - | 977 7 | E | = | | - | 305 7 | | (4) |
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Multiply both sides of equation (3) by 2 Divide both sides of equation (3) by 7, get the equation:, then subtract both sides of equation (12) from both sides of equation (2), get the equation:
| | | | 2 | A | + | | 14 | B | + | | C | + | | 93 | E | = | | 78 | | (1) |
| | | | 7 2 | C | + | | | 3535 102 | E | = | | | 203 51 | | (3) |
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Multiply both sides of equation (3) by 2 Divide both sides of equation (3) by 7, get the equation:, then subtract both sides of equation (13) from both sides of equation (1), get the equation:
| | | | 2 | A | + | | 14 | B | + | | | 4238 51 | E | = | | | 3920 51 | | (1) |
| | | | 7 2 | C | + | | | 3535 102 | E | = | | | 203 51 | | (3) |
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Multiply both sides of equation (2) by 14, get the equation: | | 14 | B | + | | | 3038 51 | E | = | | | 2744 51 | (14) | , then subtract both sides of equation (14) from both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
Where: E are arbitrary constants. 解方程组的详细方法请参阅:《多元一次方程组的解法》 |