detailed information: The input equation set is:
| | | | | -2 | A | | -1 | B | + | | 9 | C | + | | E | = | | -3 | | (3) |
| | | Question solving process:
Add both sides of equation (1) to both sides of equation (2) ,the equations are reduced to:
| | | | | -2 | A | | -1 | B | + | | 9 | C | + | | E | = | | -3 | | (3) |
| | |
Multiply both sides of equation (1) by 2, the equation can be obtained: , then add the two sides of equation (6) to both sides of equation (3), the equations are reduced to:
Divide the two sides of equation (2) by 4, the equation can be obtained: , then add the two sides of equation (7) to both sides of equation (3), the equations are reduced to:
Multiply both sides of equation (3) by 4 Divide the two sides of equation (3) by 35, the equation can be obtained: , then subtract both sides of equation (8) from both sides of equation (4), the equations are reduced to:
Multiply both sides of equation (4) by 35 Divide the two sides of equation (4) by 38, the equation can be obtained: , then add the two sides of equation (9) to both sides of equation (5), the equations are reduced to:
Multiply both sides of equation (5) by 76 Divide both sides of equation (5) by 595, get the equation:, then add the two sides of equation (10) to both sides of equation (4), get the equation:
Multiply both sides of equation (5) by 19 Divide both sides of equation (5) by 17, get the equation:, then subtract both sides of equation (11) from both sides of equation (3), get the equation:
Multiply both sides of equation (4) by 105 Divide both sides of equation (4) by 152, get the equation:, then add the two sides of equation (12) to both sides of equation (3), get the equation:
Multiply both sides of equation (4) by 105 Divide both sides of equation (4) by 38, get the equation:, then add the two sides of equation (13) to both sides of equation (2), get the equation:
Multiply both sides of equation (3) by 4 Divide both sides of equation (3) by 35, get the equation:, then add the two sides of equation (14) to both sides of equation (2), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |