detailed information: The input equation set is: Question solving process:
Subtract both sides of equation (1) from both sides of equation (2) ,the equations are reduced to:
Divide the two sides of equation (1) by 2, the equation can be obtained: , then add the two sides of equation (7) to both sides of equation (4), the equations are reduced to:
Add both sides of equation (2) to both sides of equation (3) ,the equations are reduced to:
Multiply both sides of equation (2) by 2 Divide the two sides of equation (2) by 3, the equation can be obtained: | | 4 | B | + | | | 4 3 | D | + | | | 10 3 | F | = | | | 32 3 | (8) | , then add the two sides of equation (8) to both sides of equation (4), the equations are reduced to:
Divide the two sides of equation (2) by 6, the equation can be obtained: , then subtract both sides of equation (9) from both sides of equation (6), the equations are reduced to:
| | | | | | | | - | 1 3 | D | + | | E | | - | 11 6 | F | = | | - | 8 3 | | (6) |
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交After the exchange of equation (3) and equation (4), the equation system becomes:
| | | | | | | | - | 1 3 | D | + | | E | | - | 11 6 | F | = | | - | 8 3 | | (6) |
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Add both sides of equation (3) to both sides of equation (5) ,the equations are reduced to:
| | | | | | | | - | 1 3 | D | + | | E | | - | 11 6 | F | = | | - | 8 3 | | (6) |
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Multiply both sides of equation (4) by 7 Divide the two sides of equation (4) by 6, the equation can be obtained: | | | 7 3 | D | + | | | 7 2 | E | + | | | 35 6 | F | = | | | 56 3 | (10) | , then subtract both sides of equation (10) from both sides of equation (5), the equations are reduced to:
| | | | | | | | - | 1 3 | D | + | | E | | - | 11 6 | F | = | | - | 8 3 | | (6) |
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Divide the two sides of equation (4) by 6, the equation can be obtained: | | | 1 3 | D | + | | | 1 2 | E | + | | | 5 6 | F | = | | | 8 3 | (11) | , then add the two sides of equation (11) to both sides of equation (6), the equations are reduced to:
Divide the two sides of equation (5) by 3, the equation can be obtained: , then add the two sides of equation (12) to both sides of equation (6), the equations are reduced to:
Multiply both sides of equation (6) by 15 Divide both sides of equation (6) by 8, get the equation:, then subtract both sides of equation (13) from both sides of equation (5), get the equation:
Multiply both sides of equation (6) by 15 Divide both sides of equation (6) by 8, get the equation:, then add the two sides of equation (14) to both sides of equation (4), get the equation:
Multiply both sides of equation (6) by 5 Divide both sides of equation (6) by 16, get the equation:, then add the two sides of equation (15) to both sides of equation (3), get the equation:
Multiply both sides of equation (6) by 15 Divide both sides of equation (6) by 8, get the equation:, then add the two sides of equation (16) to both sides of equation (2), get the equation:
Multiply both sides of equation (6) by 15 Divide both sides of equation (6) by 8, get the equation:, then subtract both sides of equation (17) from both sides of equation (1), get the equation:
Multiply both sides of equation (5) by 2 Divide both sides of equation (5) by 3, get the equation:, then add the two sides of equation (18) to both sides of equation (4), get the equation:
Multiply both sides of equation (4) by 2 Divide both sides of equation (4) by 3, get the equation:, then subtract both sides of equation (19) from both sides of equation (3), get the equation:
Subtract both sides of equation (4) from both sides of equation (2), get the equation:
Add both sides of equation (2) to both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |