detailed information: The input equation set is:
| | | | | | 510 | A | + | | 510 | C | + | | 510 | E | = | | 5 | | (3) |
| | 3000 | B | + | | 330 | D | + | | 510 | E | = | | 12 | | (4) |
| | 510 | A | + | | 3000 | B | + | | 510 | C | + | | 330 | D | = | | 17 | | (5) |
| Question solving process:
Multiply both sides of equation (1) by 510, the equation can be obtained: | | 510 | A | + | | 510 | B | | -510 | E | = | | 0 | (6) | , then subtract both sides of equation (6) from both sides of equation (3), the equations are reduced to:
| | | | | -510 | B | + | | 510 | C | + | | 1020 | E | = | | 5 | | (3) |
| | 3000 | B | + | | 330 | D | + | | 510 | E | = | | 12 | | (4) |
| | 510 | A | + | | 3000 | B | + | | 510 | C | + | | 330 | D | = | | 17 | | (5) |
|
Multiply both sides of equation (1) by 510, the equation can be obtained: | | 510 | A | + | | 510 | B | | -510 | E | = | | 0 | (7) | , then subtract both sides of equation (7) from both sides of equation (5), the equations are reduced to:
| | | | | -510 | B | + | | 510 | C | + | | 1020 | E | = | | 5 | | (3) |
| | 3000 | B | + | | 330 | D | + | | 510 | E | = | | 12 | | (4) |
| | 2490 | B | + | | 510 | C | + | | 330 | D | + | | 510 | E | = | | 17 | | (5) |
|
交After the exchange of equation (2) and equation (3), the equation system becomes:
| | | | -510 | B | + | | 510 | C | + | | 1020 | E | = | | 5 | | (2) |
| | | 3000 | B | + | | 330 | D | + | | 510 | E | = | | 12 | | (4) |
| | 2490 | B | + | | 510 | C | + | | 330 | D | + | | 510 | E | = | | 17 | | (5) |
|
Multiply both sides of equation (2) by 100 Divide the two sides of equation (2) by 17, the equation can be obtained: | -3000 | B | + | | 3000 | C | + | | 6000 | E | = | | | 500 17 | (8) | , then add the two sides of equation (8) to both sides of equation (4), the equations are reduced to:
| | | | -510 | B | + | | 510 | C | + | | 1020 | E | = | | 5 | | (2) |
| | | 3000 | C | + | | 330 | D | + | | 6510 | E | = | | | 704 17 | | (4) |
| | 2490 | B | + | | 510 | C | + | | 330 | D | + | | 510 | E | = | | 17 | | (5) |
|
Multiply both sides of equation (2) by 83 Divide the two sides of equation (2) by 17, the equation can be obtained: | -2490 | B | + | | 2490 | C | + | | 4980 | E | = | | | 415 17 | (9) | , then add the two sides of equation (9) to both sides of equation (5), the equations are reduced to:
| | | | -510 | B | + | | 510 | C | + | | 1020 | E | = | | 5 | | (2) |
| | | 3000 | C | + | | 330 | D | + | | 6510 | E | = | | | 704 17 | | (4) |
| | 3000 | C | + | | 330 | D | + | | 5490 | E | = | | | 704 17 | | (5) |
|
Multiply both sides of equation (3) by 3000, the equation can be obtained: | | 3000 | C | + | | 3000 | D | | -3000 | E | = | | 0 | (10) | , then subtract both sides of equation (10) from both sides of equation (4), the equations are reduced to:
| | | | -510 | B | + | | 510 | C | + | | 1020 | E | = | | 5 | | (2) |
| | -2670 | D | + | | 9510 | E | = | | | 704 17 | | (4) |
| | 3000 | C | + | | 330 | D | + | | 5490 | E | = | | | 704 17 | | (5) |
|
Multiply both sides of equation (3) by 3000, the equation can be obtained: | | 3000 | C | + | | 3000 | D | | -3000 | E | = | | 0 | (11) | , then subtract both sides of equation (11) from both sides of equation (5), the equations are reduced to:
| | | | -510 | B | + | | 510 | C | + | | 1020 | E | = | | 5 | | (2) |
| | -2670 | D | + | | 9510 | E | = | | | 704 17 | | (4) |
| -2670 | D | + | | 8490 | E | = | | | 704 17 | | (5) |
|
Subtract both sides of equation (4) from both sides of equation (5) ,the equations are reduced to:
| | | | -510 | B | + | | 510 | C | + | | 1020 | E | = | | 5 | | (2) |
| | -2670 | D | + | | 9510 | E | = | | | 704 17 | | (4) |
| |
Multiply both sides of equation (5) by 317 Divide both sides of equation (5) by 34, get the equation:, then add the two sides of equation (12) to both sides of equation (4), get the equation:
| | | | -510 | B | + | | 510 | C | + | | 1020 | E | = | | 5 | | (2) |
| | | |
Divide both sides of equation (5) by 1020, get the equation:, then subtract both sides of equation (13) from both sides of equation (3), get the equation:
| | | | -510 | B | + | | 510 | C | + | | 1020 | E | = | | 5 | | (2) |
| | | |
Add both sides of equation (5) to both sides of equation (2), get the equation:
Divide both sides of equation (5) by 1020, get the equation:, then subtract both sides of equation (14) from both sides of equation (1), get the equation:
Divide both sides of equation (4) by 2670, get the equation:, then add the two sides of equation (15) to both sides of equation (3), get the equation:
Multiply both sides of equation (3) by 510, get the equation:, then subtract both sides of equation (16) from both sides of equation (2), get the equation:
Divide both sides of equation (2) by 510, get the equation:, then add the two sides of equation (17) to both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |