detailed information: The input equation set is:
 | | | - | 1 10 | A | + | | | 1 10 | B | + | | C | = | | 0 | | (1) |
| | | | Question solving process:
Multiply both sides of equation (1) by 20, the equation can be obtained: , then subtract both sides of equation (5) from both sides of equation (2), the equations are reduced to:
 | | | - | 1 10 | A | + | | | 1 10 | B | + | | C | = | | 0 | | (1) |
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Multiply both sides of equation (1) by 50, the equation can be obtained: , then add the two sides of equation (6) to both sides of equation (3), the equations are reduced to:
 | | | - | 1 10 | A | + | | | 1 10 | B | + | | C | = | | 0 | | (1) |
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Add both sides of equation (2) to both sides of equation (3) ,the equations are reduced to:
 | | | - | 1 10 | A | + | | | 1 10 | B | + | | C | = | | 0 | | (1) |
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Divide the two sides of equation (2) by 5, the equation can be obtained: , then add the two sides of equation (7) to both sides of equation (4), the equations are reduced to:
 | | | - | 1 10 | A | + | | | 1 10 | B | + | | C | = | | 0 | | (1) |
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Multiply both sides of equation (3) by 4 Divide the two sides of equation (3) by 31, the equation can be obtained: , then add the two sides of equation (8) to both sides of equation (4), the equations are reduced to:
 | | | - | 1 10 | A | + | | | 1 10 | B | + | | C | = | | 0 | | (1) |
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Multiply both sides of equation (4) by 155 Divide both sides of equation (4) by 1601, get the equation: | | | 16010 1601 | D | = | | | 2260 1601 | (9) | , then subtract both sides of equation (9) from both sides of equation (3), get the equation:
 | | | - | 1 10 | A | + | | | 1 10 | B | + | | C | = | | 0 | | (1) |
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Multiply both sides of equation (4) by 155 Divide both sides of equation (4) by 1601, get the equation: | | | 16010 1601 | D | = | | | 2260 1601 | (10) | , then subtract both sides of equation (10) from both sides of equation (2), get the equation:
 | | | - | 1 10 | A | + | | | 1 10 | B | + | | C | = | | 0 | | (1) |
| -5 | B | | -20 | C | = | | - | 2260 1601 | | (2) |
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Multiply both sides of equation (3) by 20 Divide both sides of equation (3) by 31, get the equation:, then add the two sides of equation (11) to both sides of equation (2), get the equation:
 | | | - | 1 10 | A | + | | | 1 10 | B | + | | C | = | | 0 | | (1) |
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Divide both sides of equation (3) by 31, get the equation:, then subtract both sides of equation (12) from both sides of equation (1), get the equation:
 | | | - | 1 10 | A | + | | | 1 10 | B | = | | - | 5763 1601 | | (1) |
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Divide both sides of equation (2) by 50, get the equation:, then add the two sides of equation (13) to both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |