detailed information: The input equation set is:
| | | | 50 | A | + | | 23 | B | + | | 6 | C | + | | 10 | D | = | | 0 | | (1) |
| | 15 | A | + | | 30 | B | + | | 20 | C | + | | 10 | D | = | | 0 | | (2) |
| | 90 | A | + | | 50 | B | + | | 60 | C | + | | 10 | D | = | | 0 | | (3) |
| | 2 | A | + | | 6 | B | + | | 20 | C | + | | 10 | D | = | | 0 | | (4) |
| Question solving process:
Multiply both sides of equation (1) by 3 Divide the two sides of equation (1) by 10, the equation can be obtained: | | 15 | A | + | | | 69 10 | B | + | | | 9 5 | C | + | | 3 | D | = | | 0 | (5) | , then subtract both sides of equation (5) from both sides of equation (2), the equations are reduced to:
| | | | 50 | A | + | | 23 | B | + | | 6 | C | + | | 10 | D | = | | 0 | | (1) |
| | | 231 10 | B | + | | | 91 5 | C | + | | 7 | D | = | | 0 | | (2) |
| | 90 | A | + | | 50 | B | + | | 60 | C | + | | 10 | D | = | | 0 | | (3) |
| | 2 | A | + | | 6 | B | + | | 20 | C | + | | 10 | D | = | | 0 | | (4) |
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Multiply both sides of equation (1) by 9 Divide the two sides of equation (1) by 5, the equation can be obtained: | | 90 | A | + | | | 207 5 | B | + | | | 54 5 | C | + | | 18 | D | = | | 0 | (6) | , then subtract both sides of equation (6) from both sides of equation (3), the equations are reduced to:
| | | | 50 | A | + | | 23 | B | + | | 6 | C | + | | 10 | D | = | | 0 | | (1) |
| | | 231 10 | B | + | | | 91 5 | C | + | | 7 | D | = | | 0 | | (2) |
| | | 2 | A | + | | 6 | B | + | | 20 | C | + | | 10 | D | = | | 0 | | (4) |
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Divide the two sides of equation (1) by 25, the equation can be obtained: | | 2 | A | + | | | 23 25 | B | + | | | 6 25 | C | + | | | 2 5 | D | = | | 0 | (7) | , then subtract both sides of equation (7) from both sides of equation (4), the equations are reduced to:
| | | | 50 | A | + | | 23 | B | + | | 6 | C | + | | 10 | D | = | | 0 | | (1) |
| | | 231 10 | B | + | | | 91 5 | C | + | | 7 | D | = | | 0 | | (2) |
| | | | 127 25 | B | + | | | 494 25 | C | + | | | 48 5 | D | = | | 0 | | (4) |
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Multiply both sides of equation (2) by 86 Divide the two sides of equation (2) by 231, the equation can be obtained: | | | 43 5 | B | + | | | 1118 165 | C | + | | | 86 33 | D | = | | 0 | (8) | , then subtract both sides of equation (8) from both sides of equation (3), the equations are reduced to:
| | | | 50 | A | + | | 23 | B | + | | 6 | C | + | | 10 | D | = | | 0 | | (1) |
| | | 231 10 | B | + | | | 91 5 | C | + | | 7 | D | = | | 0 | | (2) |
| | | | 127 25 | B | + | | | 494 25 | C | + | | | 48 5 | D | = | | 0 | | (4) |
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Multiply both sides of equation (2) by 254 Divide the two sides of equation (2) by 1155, the equation can be obtained: | | | 127 25 | B | + | | | 3302 825 | C | + | | | 254 165 | D | = | | 0 | (9) | , then subtract both sides of equation (9) from both sides of equation (4), the equations are reduced to:
| | | | 50 | A | + | | 23 | B | + | | 6 | C | + | | 10 | D | = | | 0 | | (1) |
| | | 231 10 | B | + | | | 91 5 | C | + | | 7 | D | = | | 0 | | (2) |
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Multiply both sides of equation (3) by 13 Divide the two sides of equation (3) by 35, the equation can be obtained: , then subtract both sides of equation (10) from both sides of equation (4), the equations are reduced to:
| | | | 50 | A | + | | 23 | B | + | | 6 | C | + | | 10 | D | = | | 0 | | (1) |
| | | 231 10 | B | + | | | 91 5 | C | + | | 7 | D | = | | 0 | | (2) |
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Multiply both sides of equation (4) by 175 Divide both sides of equation (4) by 198, get the equation:, then add the two sides of equation (11) to both sides of equation (3), get the equation:
| | | | 50 | A | + | | 23 | B | + | | 6 | C | + | | 10 | D | = | | 0 | | (1) |
| | | 231 10 | B | + | | | 91 5 | C | + | | 7 | D | = | | 0 | | (2) |
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Multiply both sides of equation (4) by 7 Divide both sides of equation (4) by 12, get the equation:, then subtract both sides of equation (12) from both sides of equation (2), get the equation:
| | | | 50 | A | + | | 23 | B | + | | 6 | C | + | | 10 | D | = | | 0 | | (1) |
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Multiply both sides of equation (4) by 5 Divide both sides of equation (4) by 6, get the equation:, then subtract both sides of equation (13) from both sides of equation (1), get the equation:
Multiply both sides of equation (3) by 429 Divide both sides of equation (3) by 1000, get the equation:, then subtract both sides of equation (14) from both sides of equation (2), get the equation:
Multiply both sides of equation (3) by 99 Divide both sides of equation (3) by 700, get the equation:, then subtract both sides of equation (15) from both sides of equation (1), get the equation:
Multiply both sides of equation (2) by 230 Divide both sides of equation (2) by 231, get the equation:, then subtract both sides of equation (16) from both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |