detailed information: The input equation set is:
 | | | | 14 | A | + | | 6 | B | + | | 11 | C | | -1 | D | = | | 0 | | (1) |
| -2 | A | + | | 12 | B | | -6 | C | | -1 | D | = | | 0 | | (2) |
| -12 | A | + | | 6 | B | + | | 10 | C | | -1 | D | = | | 0 | | (3) |
| | Question solving process:
Divide the two sides of equation (1) by 7, the equation can be obtained: | | 2 | A | + | | | 6 7 | B | + | | | 11 7 | C | | - | 1 7 | D | = | | 0 | (5) | , then add the two sides of equation (5) to both sides of equation (2), the equations are reduced to:
 | | | | 14 | A | + | | 6 | B | + | | 11 | C | | -1 | D | = | | 0 | | (1) |
| | | 90 7 | B | | - | 31 7 | C | | - | 8 7 | D | = | | 0 | | (2) |
| -12 | A | + | | 6 | B | + | | 10 | C | | -1 | D | = | | 0 | | (3) |
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Multiply both sides of equation (1) by 6 Divide the two sides of equation (1) by 7, the equation can be obtained: | | 12 | A | + | | | 36 7 | B | + | | | 66 7 | C | | - | 6 7 | D | = | | 0 | (6) | , then add the two sides of equation (6) to both sides of equation (3), the equations are reduced to:
 | | | | 14 | A | + | | 6 | B | + | | 11 | C | | -1 | D | = | | 0 | | (1) |
| | | 90 7 | B | | - | 31 7 | C | | - | 8 7 | D | = | | 0 | | (2) |
| | | 78 7 | B | + | | | 136 7 | C | | - | 13 7 | D | = | | 0 | | (3) |
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Divide the two sides of equation (1) by 14, the equation can be obtained: | | A | + | | | 3 7 | B | + | | | 11 14 | C | | - | 1 14 | D | = | | 0 | (7) | , then subtract both sides of equation (7) from both sides of equation (4), the equations are reduced to:
 | | | | 14 | A | + | | 6 | B | + | | 11 | C | | -1 | D | = | | 0 | | (1) |
| | | 90 7 | B | | - | 31 7 | C | | - | 8 7 | D | = | | 0 | | (2) |
| | | 78 7 | B | + | | | 136 7 | C | | - | 13 7 | D | = | | 0 | | (3) |
| | | 4 7 | B | + | | | 3 14 | C | + | | | 1 14 | D | = | | 1 | | (4) |
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Multiply both sides of equation (2) by 13 Divide the two sides of equation (2) by 15, the equation can be obtained: | | | 78 7 | B | | - | 403 105 | C | | - | 104 105 | D | = | | 0 | (8) | , then subtract both sides of equation (8) from both sides of equation (3), the equations are reduced to:
 | | | | 14 | A | + | | 6 | B | + | | 11 | C | | -1 | D | = | | 0 | | (1) |
| | | 90 7 | B | | - | 31 7 | C | | - | 8 7 | D | = | | 0 | | (2) |
| | | | 4 7 | B | + | | | 3 14 | C | + | | | 1 14 | D | = | | 1 | | (4) |
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Multiply both sides of equation (2) by 2 Divide the two sides of equation (2) by 45, the equation can be obtained: | | | 4 7 | B | | - | 62 315 | C | | - | 16 315 | D | = | | 0 | (9) | , then subtract both sides of equation (9) from both sides of equation (4), the equations are reduced to:
 | | | | 14 | A | + | | 6 | B | + | | 11 | C | | -1 | D | = | | 0 | | (1) |
| | | 90 7 | B | | - | 31 7 | C | | - | 8 7 | D | = | | 0 | | (2) |
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Multiply both sides of equation (3) by 37 Divide the two sides of equation (3) by 2094, the equation can be obtained: | | | 12913 31410 | C | | - | 481 31410 | D | = | | 0 | (10) | , then subtract both sides of equation (10) from both sides of equation (4), the equations are reduced to:
 | | | | 14 | A | + | | 6 | B | + | | 11 | C | | -1 | D | = | | 0 | | (1) |
| | | 90 7 | B | | - | 31 7 | C | | - | 8 7 | D | = | | 0 | | (2) |
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Multiply both sides of equation (4) by 4537 Divide both sides of equation (4) by 720, get the equation:, then add the two sides of equation (11) to both sides of equation (3), get the equation:
 | | | | 14 | A | + | | 6 | B | + | | 11 | C | | -1 | D | = | | 0 | | (1) |
| | | 90 7 | B | | - | 31 7 | C | | - | 8 7 | D | = | | 0 | | (2) |
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Multiply both sides of equation (4) by 349 Divide both sides of equation (4) by 42, get the equation: | | | 2792 2443 | D | = | | | 121801 14658 | (12) | , then add the two sides of equation (12) to both sides of equation (2), get the equation:
 | | | | 14 | A | + | | 6 | B | + | | 11 | C | | -1 | D | = | | 0 | | (1) |
| | | 90 7 | B | | - | 31 7 | C | = | | | 121801 14658 | | (2) |
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Multiply both sides of equation (4) by 349 Divide both sides of equation (4) by 48, get the equation:, then add the two sides of equation (13) to both sides of equation (1), get the equation:
 | | | | 14 | A | + | | 6 | B | + | | 11 | C | = | | | 121801 16752 | | (1) |
| | | 90 7 | B | | - | 31 7 | C | = | | | 121801 14658 | | (2) |
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Multiply both sides of equation (3) by 465 Divide both sides of equation (3) by 2443, get the equation: | | | 10819 2443 | C | = | | | 140647 117264 | (14) | , then add the two sides of equation (14) to both sides of equation (2), get the equation:
 | | | | 14 | A | + | | 6 | B | + | | 11 | C | = | | | 121801 16752 | | (1) |
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Multiply both sides of equation (3) by 165 Divide both sides of equation (3) by 349, get the equation: | | | 3839 349 | C | = | | | 49907 16752 | (15) | , then subtract both sides of equation (15) from both sides of equation (1), get the equation:
Multiply both sides of equation (2) by 7 Divide both sides of equation (2) by 15, get the equation:, then subtract both sides of equation (16) from both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |