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On line solution of multivariate equations：
    First set the elements of the equation (i.e. the number of unknowns), then click the "Next" button to enter the coefficients of each element of the equation set, and click the "Next" button to obtain the solution of the equation set.
    Note that the coefficients of each element of the equation system can only be numbers, not algebraic expressions (including mathematical functions).
    Current location：Equations > Multivariate equations > Answer
detailed information：
The input equation set is:
 2C -2D -1E = -10    (1)
 A -4B + E = -5    (2)
 B -1D + E = 0    (3)
 A -1C -1E = 0    (4)
 A + B = 20    (5)
Question solving process:

交After the exchange of equation (1) and equation (2)， the equation system becomes:
 A -4B + E = -5    (1)
 2C -2D -1E = -10    (2)
 B -1D + E = 0    (3)
 A -1C -1E = 0    (4)
 A + B = 20    (5)

Subtract both sides of equation (1) from both sides of equation (4) ,the equations are reduced to:
 A -4B + E = -5    (1)
 2C -2D -1E = -10    (2)
 B -1D + E = 0    (3)
 4B -1C -2E = 5    (4)
 A + B = 20    (5)

Subtract both sides of equation (1) from both sides of equation (5) ,the equations are reduced to:
 A -4B + E = -5    (1)
 2C -2D -1E = -10    (2)
 B -1D + E = 0    (3)
 4B -1C -2E = 5    (4)
 5B -1E = 25    (5)

交After the exchange of equation (2) and equation (3)， the equation system becomes:
 A -4B + E = -5    (1)
 B -1D + E = 0    (2)
 2C -2D -1E = -10    (3)
 4B -1C -2E = 5    (4)
 5B -1E = 25    (5)

Multiply both sides of equation (2) by 4, the equation can be obtained:
         4B -4D + 4E = 0    (6)
, then subtract both sides of equation (6) from both sides of equation (4), the equations are reduced to:
 A -4B + E = -5    (1)
 B -1D + E = 0    (2)
 2C -2D -1E = -10    (3)
-1C + 4D -6E = 5    (4)
 5B -1E = 25    (5)

Multiply both sides of equation (2) by 5, the equation can be obtained:
         5B -5D + 5E = 0    (7)
, then subtract both sides of equation (7) from both sides of equation (5), the equations are reduced to:
 A -4B + E = -5    (1)
 B -1D + E = 0    (2)
 2C -2D -1E = -10    (3)
-1C + 4D -6E = 5    (4)
 5D -6E = 25    (5)

Divide the two sides of equation (3) by 2, the equation can be obtained:
         C -1D - 
1
2
E = -5    (8)
, then add the two sides of equation (8) to both sides of equation (4), the equations are reduced to:
 A -4B + E = -5    (1)
 B -1D + E = 0    (2)
 2C -2D -1E = -10    (3)
 3D - 
13
2
E = 0    (4)
 5D -6E = 25    (5)

Multiply both sides of equation (4) by 5
Divide the two sides of equation (4) by 3, the equation can be obtained:
         5D - 
65
6
E = 0    (9)
, then subtract both sides of equation (9) from both sides of equation (5), the equations are reduced to:
 A -4B + E = -5    (1)
 B -1D + E = 0    (2)
 2C -2D -1E = -10    (3)
 3D - 
13
2
E = 0    (4)
 
29
6
E = 25    (5)

Multiply both sides of equation (5) by 39
Divide both sides of equation (5) by 29, get the equation：
         
13
2
E = 
975
29
    (10)
, then add the two sides of equation (10) to both sides of equation (4), get the equation：
 A -4B + E = -5    (1)
 B -1D + E = 0    (2)
 2C -2D -1E = -10    (3)
 3D = 
975
29
    (4)
 
29
6
E = 25    (5)

Multiply both sides of equation (5) by 6
Divide both sides of equation (5) by 29, get the equation：
         E = 
150
29
    (11)
, then add the two sides of equation (11) to both sides of equation (3), get the equation：
 A -4B + E = -5    (1)
 B -1D + E = 0    (2)
 2C -2D = - 
140
29
    (3)
 3D = 
975
29
    (4)
 
29
6
E = 25    (5)

Multiply both sides of equation (5) by 6
Divide both sides of equation (5) by 29, get the equation：
         E = 
150
29
    (12)
, then subtract both sides of equation (12) from both sides of equation (2), get the equation：
 A -4B + E = -5    (1)
 B -1D = - 
150
29
    (2)
 2C -2D = - 
140
29
    (3)
 3D = 
975
29
    (4)
 
29
6
E = 25    (5)

Multiply both sides of equation (5) by 6
Divide both sides of equation (5) by 29, get the equation：
         E = 
150
29
    (13)
, then subtract both sides of equation (13) from both sides of equation (1), get the equation：
 A -4B = - 
295
29
    (1)
 B -1D = - 
150
29
    (2)
 2C -2D = - 
140
29
    (3)
 3D = 
975
29
    (4)
 
29
6
E = 25    (5)

Multiply both sides of equation (4) by 2
Divide both sides of equation (4) by 3, get the equation：
         2D = 
650
29
    (14)
, then add the two sides of equation (14) to both sides of equation (3), get the equation：
 A -4B = - 
295
29
    (1)
 B -1D = - 
150
29
    (2)
 2C = 
510
29
    (3)
 3D = 
975
29
    (4)
 E = 
150
29
    (5)

Divide both sides of equation (4) by 3, get the equation：
         D = 
325
29
    (15)
, then add the two sides of equation (15) to both sides of equation (2), get the equation：
 A -4B = - 
295
29
    (1)
 B = 
175
29
    (2)
 2C = 
510
29
    (3)
 3D = 
975
29
    (4)
 E = 
150
29
    (5)

Multiply both sides of equation (2) by 4, get the equation：
         4B = 
700
29
    (16)
, then add the two sides of equation (16) to both sides of equation (1), get the equation：
 A = 
405
29
    (1)
 B = 
175
29
    (2)
 C = 
255
29
    (3)
 D = 
325
29
    (4)
 E = 
150
29
    (5)

The coefficient of the unknown number is reduced to 1, and the equations are reduced to：
 A = 
405
29
    (1)
 B = 
175
29
    (2)
 C = 
255
29
    (3)
 D = 
325
29
    (4)
 E = 
150
29
    (5)


Therefore, the solution of the equation set is:
A = 
405
29
B = 
175
29
C = 
255
29
D = 
325
29
E = 
150
29


Convert the solution of the equation set to decimals:
A = 13.965517
B = 6.034483
C = 8.793103
D = 11.206897
E = 5.172414

解方程组的详细方法请参阅：《多元一次方程组的解法》
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