detailed information: The input equation set is: Question solving process:
Divide the two sides of equation (1) by 3, the equation can be obtained: , then add the two sides of equation (6) to both sides of equation (2), the equations are reduced to:
Divide the two sides of equation (1) by 6, the equation can be obtained: , then subtract both sides of equation (7) from both sides of equation (4), the equations are reduced to:
Divide the two sides of equation (2) by 28, the equation can be obtained: | | | 1 3 | B | | - | 1 21 | C | + | | | 1 28 | E | = | | | 1 7 | (8) | , then subtract both sides of equation (8) from both sides of equation (4), the equations are reduced to:
 | | | | | | | | 5 7 | C | | -2 | D | | - | 1 28 | E | = | | - | 15 7 | | (4) |
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Multiply both sides of equation (2) by 3 Divide the two sides of equation (2) by 28, the equation can be obtained: , then add the two sides of equation (9) to both sides of equation (5), the equations are reduced to:
 | | | | | | | | 5 7 | C | | -2 | D | | - | 1 28 | E | = | | - | 15 7 | | (4) |
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Multiply both sides of equation (3) by 5 Divide the two sides of equation (3) by 7, the equation can be obtained: , then subtract both sides of equation (10) from both sides of equation (4), the equations are reduced to:
 | | | | | | - | 24 7 | D | | - | 1 28 | E | = | | - | 15 7 | | (4) |
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Multiply both sides of equation (3) by 6 Divide the two sides of equation (3) by 7, the equation can be obtained: , then subtract both sides of equation (11) from both sides of equation (5), the equations are reduced to:
 | | | | | | - | 24 7 | D | | - | 1 28 | E | = | | - | 15 7 | | (4) |
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Divide the two sides of equation (4) by 2, the equation can be obtained: | - | 12 7 | D | | - | 1 56 | E | = | | - | 15 14 | (12) | , then subtract both sides of equation (12) from both sides of equation (5), the equations are reduced to:
 | | | | | | - | 24 7 | D | | - | 1 28 | E | = | | - | 15 7 | | (4) |
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Multiply both sides of equation (5) by 2 Divide both sides of equation (5) by 7, get the equation:, then add the two sides of equation (13) to both sides of equation (4), get the equation:
Multiply both sides of equation (5) by 8, get the equation:, then subtract both sides of equation (14) from both sides of equation (2), get the equation:
Multiply both sides of equation (4) by 7 Divide both sides of equation (4) by 12, get the equation:, then add the two sides of equation (15) to both sides of equation (3), get the equation:
Multiply both sides of equation (3) by 4 Divide both sides of equation (3) by 3, get the equation:, then add the two sides of equation (16) to both sides of equation (2), get the equation:
Multiply both sides of equation (3) by 4, get the equation:, then add the two sides of equation (17) to both sides of equation (1), get the equation:
Multiply both sides of equation (2) by 3 Divide both sides of equation (2) by 14, get the equation:, then add the two sides of equation (18) to both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |