detailed information: The input equation set is:
| | | | | | 100 | A | + | | 3 | B | + | | 3 | C | | -1 | D | = | | 0 | | (3) |
| | 100 | A | + | | 3 | B | + | | 3 | C | + | | 3 | D | | -1 | E | = | | 0 | | (4) |
| | 100 | A | + | | 3 | B | + | | 3 | C | + | | 3 | D | + | | 3 | E | | -1 | F | = | | 0 | | (5) |
| | B | + | | C | + | | D | + | | E | + | | F | = | | 50 | | (6) |
| Question solving process:
Subtract both sides of equation (1) from both sides of equation (2) ,the equations are reduced to:
| | | | | | 100 | A | + | | 3 | B | + | | 3 | C | | -1 | D | = | | 0 | | (3) |
| | 100 | A | + | | 3 | B | + | | 3 | C | + | | 3 | D | | -1 | E | = | | 0 | | (4) |
| | 100 | A | + | | 3 | B | + | | 3 | C | + | | 3 | D | + | | 3 | E | | -1 | F | = | | 0 | | (5) |
| | B | + | | C | + | | D | + | | E | + | | F | = | | 50 | | (6) |
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Subtract both sides of equation (1) from both sides of equation (3) ,the equations are reduced to:
| | | | | | | 100 | A | + | | 3 | B | + | | 3 | C | + | | 3 | D | | -1 | E | = | | 0 | | (4) |
| | 100 | A | + | | 3 | B | + | | 3 | C | + | | 3 | D | + | | 3 | E | | -1 | F | = | | 0 | | (5) |
| | B | + | | C | + | | D | + | | E | + | | F | = | | 50 | | (6) |
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Subtract both sides of equation (1) from both sides of equation (4) ,the equations are reduced to:
| | | | | | | 4 | B | + | | 3 | C | + | | 3 | D | | -1 | E | = | | -150 | | (4) |
| | 100 | A | + | | 3 | B | + | | 3 | C | + | | 3 | D | + | | 3 | E | | -1 | F | = | | 0 | | (5) |
| | B | + | | C | + | | D | + | | E | + | | F | = | | 50 | | (6) |
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Subtract both sides of equation (1) from both sides of equation (5) ,the equations are reduced to:
| | | | | | | 4 | B | + | | 3 | C | + | | 3 | D | | -1 | E | = | | -150 | | (4) |
| | 4 | B | + | | 3 | C | + | | 3 | D | + | | 3 | E | | -1 | F | = | | -150 | | (5) |
| | B | + | | C | + | | D | + | | E | + | | F | = | | 50 | | (6) |
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Subtract both sides of equation (2) from both sides of equation (3) ,the equations are reduced to:
| | | | | | | 4 | B | + | | 3 | C | + | | 3 | D | | -1 | E | = | | -150 | | (4) |
| | 4 | B | + | | 3 | C | + | | 3 | D | + | | 3 | E | | -1 | F | = | | -150 | | (5) |
| | B | + | | C | + | | D | + | | E | + | | F | = | | 50 | | (6) |
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Subtract both sides of equation (2) from both sides of equation (4) ,the equations are reduced to:
| | | | | | | | 4 | B | + | | 3 | C | + | | 3 | D | + | | 3 | E | | -1 | F | = | | -150 | | (5) |
| | B | + | | C | + | | D | + | | E | + | | F | = | | 50 | | (6) |
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Subtract both sides of equation (2) from both sides of equation (5) ,the equations are reduced to:
| | | | | | | | 4 | C | + | | 3 | D | + | | 3 | E | | -1 | F | = | | -150 | | (5) |
| | B | + | | C | + | | D | + | | E | + | | F | = | | 50 | | (6) |
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Divide the two sides of equation (2) by 4, the equation can be obtained: , then subtract both sides of equation (7) from both sides of equation (6), the equations are reduced to:
| | | | | | | | 4 | C | + | | 3 | D | + | | 3 | E | | -1 | F | = | | -150 | | (5) |
| |
Subtract both sides of equation (3) from both sides of equation (4) ,the equations are reduced to:
| | | | | | | | 4 | C | + | | 3 | D | + | | 3 | E | | -1 | F | = | | -150 | | (5) |
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Subtract both sides of equation (3) from both sides of equation (5) ,the equations are reduced to:
Multiply both sides of equation (3) by 5 Divide the two sides of equation (3) by 16, the equation can be obtained: , then subtract both sides of equation (8) from both sides of equation (6), the equations are reduced to:
Subtract both sides of equation (4) from both sides of equation (5) ,the equations are reduced to:
Multiply both sides of equation (4) by 21 Divide the two sides of equation (4) by 64, the equation can be obtained: , then subtract both sides of equation (9) from both sides of equation (6), the equations are reduced to:
Multiply both sides of equation (5) by 85 Divide the two sides of equation (5) by 256, the equation can be obtained: , then subtract both sides of equation (10) from both sides of equation (6), the equations are reduced to:
Multiply both sides of equation (6) by 256 Divide both sides of equation (6) by 341, get the equation:, then add the two sides of equation (11) to both sides of equation (5), get the equation:
Divide both sides of equation (5) by 4, get the equation:, then add the two sides of equation (12) to both sides of equation (4), get the equation:
Divide both sides of equation (4) by 4, get the equation:, then add the two sides of equation (13) to both sides of equation (3), get the equation:
Divide both sides of equation (3) by 4, get the equation:, then add the two sides of equation (14) to both sides of equation (2), get the equation:
Divide both sides of equation (2) by 4, get the equation:, then add the two sides of equation (15) to both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |