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Enter the mathematical formula directly and click the "Next" button to get the calculation answer.
It supports mathematical functions (including trigonometric functions).
Current location：Mathematical operation > History of Mathematical Computation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 arithmetic calculations
[1/1 Formula]
Work: Calculate the value of equation 1+1/(1300×(6/159×10^3+20)/(500-35))×((5000/500))^2×1 .
Question type: Mathematical calculation
Solution:
1+1/(1300×(6/159×10^3+20)/(500-35))×((5000/500))^2×1
=1+1/(1300×57.736/(500-35))×((5000/500))^2×1
=1+1/(1300×57.736/465)×((5000/500))^2×1
=1+1/161.412473×((5000/500))^2×1
=1+1/161.412473×(10)^2×1
=1+1/161.412473×10^2×1
=1+1/161.412473×100×1
=1+0.006195×100×1
=1+0.6195×1
=1+0.6195
=1.6195
Answer:1+1/(1300×(6/159×10^3+20)/(500-35))×((5000/500))^2×1=1.6195