总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 1+1/(1300×(6/159×10^3+20)/(500-35))×((5000/500))^2×1 的值.
题型:数学计算
解:
1+1/(1300×(6/159×10^3+20)/(500-35))×((5000/500))^2×1
=1+1/(1300×57.736/(500-35))×((5000/500))^2×1
=1+1/(1300×57.736/465)×((5000/500))^2×1
=1+1/161.412473×((5000/500))^2×1
=1+1/161.412473×(10)^2×1
=1+1/161.412473×10^2×1
=1+1/161.412473×100×1
=1+0.006195×100×1
=1+0.6195×1
=1+0.6195
=1.6195 答案:1+1/(1300×(6/159×10^3+20)/(500-35))×((5000/500))^2×1=1.6195你的问题在这里没有得到解决?请到 热门难题 里面看看吧!