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           ☆1 arithmetic calculations

[1/1 Formula]
    Work: Calculate the value of equation 1+1/(1300×((80.39+61.25+42.75)/1816.2×10^3+23.3)/(700-35))×((7000/700))^2×1 .
    Question type: Mathematical calculation
    Solution:
          1+1/(1300×((80.39+61.25+42.75)/1816.2×10^3+23.3)/(700-35))×((7000/700))^2×1
        =1+1/(1300×(184.39/1816.2×10^3+23.3)/(700-35))×((7000/700))^2×1
        =1+1/(1300×124.825/(700-35))×((7000/700))^2×1
        =1+1/(1300×124.825/665)×((7000/700))^2×1
        =1+1/244.018797×((7000/700))^2×1
        =1+1/244.018797×(10)^2×1
        =1+1/244.018797×10^2×1
        =1+1/244.018797×100×1
        =1+0.004098×100×1
        =1+0.4098×1
        =1+0.4098
        =1.4098

    Answer:1+1/(1300×((80.39+61.25+42.75)/1816.2×10^3+23.3)/(700-35))×((7000/700))^2×1=1.4098


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