总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 1+1/(1300×((80.39+61.25+42.75)/1816.2×10^3+23.3)/(700-35))×((7000/700))^2×1 的值.
题型:数学计算
解:
1+1/(1300×((80.39+61.25+42.75)/1816.2×10^3+23.3)/(700-35))×((7000/700))^2×1
=1+1/(1300×(184.39/1816.2×10^3+23.3)/(700-35))×((7000/700))^2×1
=1+1/(1300×124.825/(700-35))×((7000/700))^2×1
=1+1/(1300×124.825/665)×((7000/700))^2×1
=1+1/244.018797×((7000/700))^2×1
=1+1/244.018797×(10)^2×1
=1+1/244.018797×10^2×1
=1+1/244.018797×100×1
=1+0.004098×100×1
=1+0.4098×1
=1+0.4098
=1.4098 答案:1+1/(1300×((80.39+61.25+42.75)/1816.2×10^3+23.3)/(700-35))×((7000/700))^2×1=1.4098你的问题在这里没有得到解决?请到 热门难题 里面看看吧!