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           ☆1 arithmetic calculations

[1/1 Formula]
    Work: Calculate the value of equation 1+1/(1300×((140.625+122.5+75.98)/2558.1×10^3+20)/(600-35))×((9900/600))^2×1 .
    Question type: Mathematical calculation
    Solution:
          1+1/(1300×((140.625+122.5+75.98)/2558.1×10^3+20)/(600-35))×((9900/600))^2×1
        =1+1/(1300×(339.105/2558.1×10^3+20)/(600-35))×((9900/600))^2×1
        =1+1/(1300×152.561/(600-35))×((9900/600))^2×1
        =1+1/(1300×152.561/565)×((9900/600))^2×1
        =1+1/351.02531×((9900/600))^2×1
        =1+1/351.02531×(16.5)^2×1
        =1+1/351.02531×16.5^2×1
        =1+1/351.02531×272.25×1
        =1+0.002849×272.25×1
        =1+0.77564×1
        =1+0.77564
        =1.77564

    Answer:1+1/(1300×((140.625+122.5+75.98)/2558.1×10^3+20)/(600-35))×((9900/600))^2×1=1.77564


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