总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 1+1/(1300×((140.625+122.5+75.98)/2558.1×10^3+20)/(600-35))×((9900/600))^2×1 的值.
题型:数学计算
解:
1+1/(1300×((140.625+122.5+75.98)/2558.1×10^3+20)/(600-35))×((9900/600))^2×1
=1+1/(1300×(339.105/2558.1×10^3+20)/(600-35))×((9900/600))^2×1
=1+1/(1300×152.561/(600-35))×((9900/600))^2×1
=1+1/(1300×152.561/565)×((9900/600))^2×1
=1+1/351.02531×((9900/600))^2×1
=1+1/351.02531×(16.5)^2×1
=1+1/351.02531×16.5^2×1
=1+1/351.02531×272.25×1
=1+0.002849×272.25×1
=1+0.77564×1
=1+0.77564
=1.77564 答案:1+1/(1300×((140.625+122.5+75.98)/2558.1×10^3+20)/(600-35))×((9900/600))^2×1=1.77564你的问题在这里没有得到解决?请到 热门难题 里面看看吧!