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It supports mathematical functions (including trigonometric functions).
Current location：Mathematical operation > History of Mathematical Computation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation a(a-1)(a+2)(a+3) = 0 .
Question type: Equation
Solution:Original question:
| a | ( | a | − | 1 | ) | ( | a | + | 2 | ) | ( | a | + | 3 | ) | = | 0 |
| Left side of the equation = | a | a | ( | a | + | 2 | ) | ( | a | + | 3 | ) | − | a | × | 1 | ( | a | + | 2 | ) | ( | a | + | 3 | ) |
| = | a | a | a | ( | a | + | 3 | ) | + | a | a | × | 2 | ( | a | + | 3 | ) | − | a | × | 1 | ( | a | + | 2 | ) | ( | a | + | 3 | ) |
| = | a | a | a | a | + | a | a | a | × | 3 | + | a | a | × | 2 | ( | a | + | 3 | ) |
| = | a | a | a | a | + | a | a | a | × | 3 | + | a | a | × | 2 | a |
| = | a | a | a | a | + | a | a | a | × | 3 | + | a | a | × | 2 | a |
| = | a | a | a | a | + | a | a | a | × | 3 | + | a | a | × | 2 | a |
| = | a | a | a | a | + | a | a | a | × | 3 | + | a | a | × | 2 | a |
| = | a | a | a | a | + | a | a | a | × | 3 | + | a | a | × | 2 | a |
| = | a | a | a | a | + | a | a | a | × | 3 | + | a | a | × | 2 | a |
| = | a | a | a | a | + | a | a | a | × | 3 | + | a | a | × | 2 | a |
| = | a | a | a | a | + | a | a | a | × | 3 | + | a | a | × | 2 | a |
| a | a | a | a | + | a | a | a | × | 3 | + | a | a | × | 2 | a | = | 0 |
After the equation is converted into a general formula, it is converted into:
( a + 3 )( a + 2 )( a - 0 )( a - 1 )=0
From
a + 3 = 0
a + 2 = 0
a - 0 = 0
a - 1 = 0
it is concluded that:：
a1=-3
a2=-2
a3=0
a4=1
There are 4 solution(s).
解程的详细方法请参阅：《方程的解法》