Overview: 1 questions will be solved this time.Among them
☆1 arithmetic calculations
[1/1 Formula]
Work: Calculate the value of equation 3^log(3,9)+log(5,1/5)+log(2,1)-lne^2 .
Question type: Mathematical calculation
Solution:
3^log(3,9)+log(5,1/5)+log(2,1)-lne^2
=3^2+log(5,1/5)+log(2,1)-lne^2
=3^2+(-1)+log(2,1)-lne^2
=3^2+(-1)+0-lne^2
=3^2.000000+-1.000000+0.000000-ln2.718282^2
=3^2.000000+-1.000000+0.000000-1^2
=9+-1+0-1^2
=9+-1+0-1
=8+0-1
=8-1
=7 Answer:3^log(3,9)+log(5,1/5)+log(2,1)-lne^2=7Your problem has not been solved here? Please go to the Hot Problems section!