Mathematics
         
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Mathematical calculation:
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           ☆1 arithmetic calculations

[1/1 Formula]
    Work: Calculate the value of equation 3^log(3,9)+log(5,1/5)+log(2,1)-lne^2 .
    Question type: Mathematical calculation
    Solution:
          3^log(3,9)+log(5,1/5)+log(2,1)-lne^2
        =3^2+log(5,1/5)+log(2,1)-lne^2
        =3^2+(-1)+log(2,1)-lne^2
        =3^2+(-1)+0-lne^2
        =3^2.000000+-1.000000+0.000000-ln2.718282^2
        =3^2.000000+-1.000000+0.000000-1^2
        =9+-1+0-1^2
        =9+-1+0-1
        =8+0-1
        =8-1
        =7

    Answer:3^log(3,9)+log(5,1/5)+log(2,1)-lne^2=7


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