总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 3^log(3,9)+log(5,1/5)+log(2,1)-lne^2 的值.
题型:数学计算
解:
3^log(3,9)+log(5,1/5)+log(2,1)-lne^2
=3^2+log(5,1/5)+log(2,1)-lne^2
=3^2+(-1)+log(2,1)-lne^2
=3^2+(-1)+0-lne^2
=3^2.000000+-1.000000+0.000000-ln2.718282^2
=3^2.000000+-1.000000+0.000000-1^2
=9+-1+0-1^2
=9+-1+0-1
=8+0-1
=8-1
=7 答案:3^log(3,9)+log(5,1/5)+log(2,1)-lne^2=7你的问题在这里没有得到解决?请到 热门难题 里面看看吧!