There are 4 questions in this calculation: for each question, the 4 derivative of x is calculated.
Note that variables are case sensitive.\[ \begin{equation}\begin{split}[1/4]Find\ the\ 4th\ derivative\ of\ function\ -cos(x)\ with\ respect\ to\ x:\\\end{split}\end{equation} \]
\[ \begin{equation}\begin{split}\\Solution:&\\ &\color{blue}{The\ first\ derivative\ function:}\\&\frac{d\left( -cos(x)\right)}{dx}\\=&--sin(x)\\=&sin(x)\\\\ &\color{blue}{The\ second\ derivative\ of\ function:} \\&\frac{d\left( sin(x)\right)}{dx}\\=&cos(x)\\=&cos(x)\\\\ &\color{blue}{The\ third\ derivative\ of\ function:} \\&\frac{d\left( cos(x)\right)}{dx}\\=&-sin(x)\\=&-sin(x)\\\\ &\color{blue}{The\ 4th\ derivative\ of\ function:} \\&\frac{d\left( -sin(x)\right)}{dx}\\=&-cos(x)\\=&-cos(x)\\ \end{split}\end{equation} \]\[ \begin{equation}\begin{split}[2/4]Find\ the\ 4th\ derivative\ of\ function\ sin(x)\ with\ respect\ to\ x:\\\end{split}\end{equation} \]
\[ \begin{equation}\begin{split}\\Solution:&\\ &\color{blue}{The\ first\ derivative\ function:}\\&\frac{d\left( sin(x)\right)}{dx}\\=&cos(x)\\=&cos(x)\\\\ &\color{blue}{The\ second\ derivative\ of\ function:} \\&\frac{d\left( cos(x)\right)}{dx}\\=&-sin(x)\\=&-sin(x)\\\\ &\color{blue}{The\ third\ derivative\ of\ function:} \\&\frac{d\left( -sin(x)\right)}{dx}\\=&-cos(x)\\=&-cos(x)\\\\ &\color{blue}{The\ 4th\ derivative\ of\ function:} \\&\frac{d\left( -cos(x)\right)}{dx}\\=&--sin(x)\\=&sin(x)\\ \end{split}\end{equation} \]\[ \begin{equation}\begin{split}[3/4]Find\ the\ 4th\ derivative\ of\ function\ ln(sec(x))\ with\ respect\ to\ x:\\\end{split}\end{equation} \]
\[ \begin{equation}\begin{split}\\Solution:&\\ &\color{blue}{The\ first\ derivative\ function:}\\&\frac{d\left( ln(sec(x))\right)}{dx}\\=&\frac{sec(x)tan(x)}{(sec(x))}\\=&tan(x)\\\\ &\color{blue}{The\ second\ derivative\ of\ function:} \\&\frac{d\left( tan(x)\right)}{dx}\\=&sec^{2}(x)(1)\\=&sec^{2}(x)\\\\ &\color{blue}{The\ third\ derivative\ of\ function:} \\&\frac{d\left( sec^{2}(x)\right)}{dx}\\=&2sec^{2}(x)tan(x)\\=&2tan(x)sec^{2}(x)\\\\ &\color{blue}{The\ 4th\ derivative\ of\ function:} \\&\frac{d\left( 2tan(x)sec^{2}(x)\right)}{dx}\\=&2sec^{2}(x)(1)sec^{2}(x) + 2tan(x)*2sec^{2}(x)tan(x)\\=&2sec^{4}(x) + 4tan^{2}(x)sec^{2}(x)\\ \end{split}\end{equation} \]\[ \begin{equation}\begin{split}[4/4]Find\ the\ 4th\ derivative\ of\ function\ -ln(csc(x))\ with\ respect\ to\ x:\\\end{split}\end{equation} \]
\[ \begin{equation}\begin{split}\\Solution:&\\ &\color{blue}{The\ first\ derivative\ function:}\\&\frac{d\left( -ln(csc(x))\right)}{dx}\\=&\frac{--csc(x)cot(x)}{(csc(x))}\\=&cot(x)\\\\ &\color{blue}{The\ second\ derivative\ of\ function:} \\&\frac{d\left( cot(x)\right)}{dx}\\=&-csc^{2}(x)\\=&-csc^{2}(x)\\\\ &\color{blue}{The\ third\ derivative\ of\ function:} \\&\frac{d\left( -csc^{2}(x)\right)}{dx}\\=&--2csc^{2}(x)cot(x)\\=&2cot(x)csc^{2}(x)\\\\ &\color{blue}{The\ 4th\ derivative\ of\ function:} \\&\frac{d\left( 2cot(x)csc^{2}(x)\right)}{dx}\\=&2*-csc^{2}(x)csc^{2}(x) + 2cot(x)*-2csc^{2}(x)cot(x)\\=&-2csc^{4}(x) - 4cot^{2}(x)csc^{2}(x)\\ \end{split}\end{equation} \]Your problem has not been solved here? Please go to the Hot Problems section!