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    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 1/(212.5-x)+1/(11.11+x) = 0.09 .
    Question type: Equation
    Solution:Original question:
     1 ÷ (
425
2
x ) + 1 ÷ (
1111
100
+ x ) =
9
100
     Multiply both sides of the equation by:(
425
2
x )
     1 + 1 ÷ (
1111
100
+ x ) × (
425
2
x ) =
9
100
(
425
2
x )
    Remove a bracket on the left of the equation::
     1 + 1 ÷ (
1111
100
+ x ) ×
425
2
1 ÷ (
1111
100
+ x ) × x =
9
100
(
425
2
x )
    Remove a bracket on the right of the equation::
     1 + 1 ÷ (
1111
100
+ x ) ×
425
2
1 ÷ (
1111
100
+ x ) × x =
9
100
×
425
2
9
100
x
    The equation is reduced to :
     1 +
425
2
÷ (
1111
100
+ x )1 ÷ (
1111
100
+ x ) × x =
153
8
9
100
x
     Multiply both sides of the equation by:(
1111
100
+ x )
     1(
1111
100
+ x ) +
425
2
1 x =
153
8
(
1111
100
+ x )
9
100
x (
1111
100
+ x )
    Remove a bracket on the left of the equation:
     1 ×
1111
100
+ 1 x +
425
2
1 x =
153
8
(
1111
100
+ x )
9
100
x (
1111
100
+ x )
    Remove a bracket on the right of the equation::
     1 ×
1111
100
+ 1 x +
425
2
1 x =
153
8
×
1111
100
+
153
8
x
9
100
x (
1111
100
+ x )
    The equation is reduced to :
     
1111
100
+ 1 x +
425
2
1 x =
169983
800
+
153
8
x
9
100
x (
1111
100
+ x )
    The equation is reduced to :
     
22361
100
+ 0 x =
169983
800
+
153
8
x
9
100
x (
1111
100
+ x )
    Remove a bracket on the right of the equation::
     
22361
100
=
169983
800
+
153
8
x
9
100
x ×
1111
100
9
100
x x
    The equation is reduced to :
     
22361
100
=
169983
800
+
153
8
x
9999
10000
x
9
100
x x
    The equation is reduced to :
     
22361
100
=
169983
800
+
181251
10000
x
9
100
x x

    
        x≈0.616019 , keep 6 decimal places
    
    There are 1 solution(s).


解一元一次方程的详细方法请参阅:《一元一次方程的解法》



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