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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (1-x)(4-x)(5-x)-12+3(4-x)-6(1-x)+2(5-x) = 0 .
    Question type: Equation
    Solution:Original question:
     (1 x )(4 x )(5 x )12 + 3(4 x )6(1 x ) + 2(5 x ) = 0
    Remove the bracket on the left of the equation:
     Left side of the equation = 1(4 x )(5 x ) x (4 x )(5 x )12 + 3(4 x )6(1 x ) + 2
                                             = 1 × 4(5 x )1 x (5 x ) x (4 x )(5 x )12 + 3(4 x )
                                             = 4(5 x )1 x (5 x ) x (4 x )(5 x )12 + 3(4 x )6
                                             = 4 × 54 x 1 x (5 x ) x (4 x )(5 x )12 + 3
                                             = 204 x 1 x (5 x ) x (4 x )(5 x )12 + 3(4 x )
                                             = 84 x 1 x (5 x ) x (4 x )(5 x ) + 3(4 x )6
                                             = 84 x 1 x × 5 + 1 x x x (4 x )(5 x )
                                             = 84 x 5 x + 1 x x x (4 x )(5 x ) + 3
                                             = 89 x + 1 x x x (4 x )(5 x ) + 3(4 x )6
                                             = 89 x + 1 x x x × 4(5 x ) + x x (5 x )
                                             = 89 x + 1 x x x × 4 × 5 + x × 4 x
                                             = 89 x + 1 x x x × 20 + x × 4 x + x
                                             = 829 x + 1 x x + x × 4 x + x x (5 x )
                                             = 829 x + 1 x x + x × 4 x + x x × 5
                                             = 829 x + 1 x x + x × 4 x + x x × 5
                                             = 829 x + 1 x x + x × 4 x + x x × 5
                                             = 2032 x + 1 x x + x × 4 x + x x × 5
                                             = 2032 x + 1 x x + x × 4 x + x x × 5
                                             = 2032 x + 1 x x + x × 4 x + x x × 5
                                             = 1426 x + 1 x x + x × 4 x + x x × 5
                                             = 1426 x + 1 x x + x × 4 x + x x × 5
                                             = 1426 x + 1 x x + x × 4 x + x x × 5
                                             = 2428 x + 1 x x + x × 4 x + x x × 5
    The equation is transformed into :
     2428 x + 1 x x + x × 4 x + x x × 5 = 0

    After the equation is converted into a general formula, it is converted into:
    ( x - 2 )( x - 2 )( x - 6 )=0
    From
        x - 2 = 0
        x - 2 = 0
        x - 6 = 0

    it is concluded that::
        x1=2
        x2=2
        x3=6
    
    There are 3 solution(s).


解程的详细方法请参阅:《方程的解法》



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