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On line Solution of Monovariate Equation：
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 3.6798 = 25.5755*0.8962(x+0.1)/[1+0.8962(x+0.1)](100-0.1081-0.0196)/100*1/(1+0.31*0.0196)+2.07(x+0.1)/1.4*0.101325 .
    Question type: Equation
    Solution:Original question:
     
18399
5000
 =
51151
2000
 ×
4481
5000
( x +
1
10
) ÷ (1 +
4481
5000
( x +
1
10
)) × (100 −
1081
10000
 −
49
2500
) ÷ 100 × 1 ÷ (1 +
31
100
 ×
49
2500
) +
207
100
( x +
1
10
) ÷
7
5
 ×
4053
40000
     Multiply both sides of the equation by:(1 +
4481
5000
( x +
1
10
))
     
18399
5000
(1 +
4481
5000
( x +
1
10
)) =
51151
2000
 ×
4481
5000
( x +
1
10
)(100 −
1081
10000
 −
49
2500
) ÷ 100 × 1 ÷ (1 +
31
100
 ×
49
2500
) +
207
100
( x +
1
10
) ÷
7
5
 ×
4053
40000
(1 +
4481
5000
( x +
1
10
))
    Remove a bracket on the left of the equation:：
     
18399
5000
 × 1 +
18399
5000
 ×
4481
5000
( x +
1
10
) =
51151
2000
 ×
4481
5000
( x +
1
10
)(100 −
1081
10000
 −
49
2500
) ÷ 100 × 1 ÷ (1 +
31
100
 ×
49
2500
) +
207
100
( x +
1
10
) ÷
7
5
 ×
4053
40000
(1 +
4481
5000
( x +
1
10
))
    Remove a bracket on the right of the equation:：
     
18399
5000
 × 1 +
18399
5000
 ×
4481
5000
( x +
1
10
) =
51151
2000
 ×
4481
5000
 x (100 −
1081
10000
 −
49
2500
) ÷ 100 × 1 ÷ (1 +
31
100
 ×
49
2500
) +
51151
2000
 ×
4481
5000
 ×
1
10
(100 −
1081
10000
 −
49
2500
) ÷ 100
    The equation is reduced to :
     
18399
5000
 +
82445919
25000000
( x +
1
10
) =
229207631
1000000000
 x (100 −
1081
10000
 −
49
2500
) ÷ (1 +
31
100
 ×
49
2500
) +
229207631
10000000000
(100 −
1081
10000
 −
49
2500
) ÷ (1 +
31
100
 ×
49
2500
) +
119853
800000
( x +
1
10
)(1 +
4481
5000
( x +
1
10
))
     Multiply both sides of the equation by:(1 +
31
100
 ×
49
2500
)
     
18399
5000
(1 +
31
100
 ×
49
2500
) +
82445919
25000000
( x +
1
10
)(1 +
31
100
 ×
49
2500
) =
229207631
1000000000
 x (100 −
1081
10000
 −
49
2500
) +
229207631
10000000000
(100 −
1081
10000
 −
49
2500
) ÷ (1 +
31
100
 ×
49
2500
) × (1 +
31
100
 ×
49
2500
) +
119853
800000
( x +
1
10
)(1 +
4481
5000
( x +
1
10
))(1 +
31
100
 ×
49
2500
)
    Remove a bracket on the left of the equation:
     
18399
5000
 × 1 +
18399
5000
 ×
31
100
 ×
49
2500
 +
82445919
25000000
( x +
1
10
)(1 +
31
100
 ×
49
2500
) =
229207631
1000000000
 x (100 −
1081
10000
 −
49
2500
) +
229207631
10000000000
(100 −
1081
10000
 −
49
2500
) ÷ (1 +
31
100
 ×
49
2500
) × (1 +
31
100
 ×
49
2500
) +
119853
800000
( x +
1
10
)(1 +
4481
5000
( x +
1
10
))(1 +
31
100
 ×
49
2500
)
    Remove a bracket on the right of the equation:：
     
18399
5000
 × 1 +
18399
5000
 ×
31
100
 ×
49
2500
 +
82445919
25000000
( x +
1
10
)(1 +
31
100
 ×
49
2500
) =
229207631
1000000000
 x × 100 −
229207631
1000000000
 x ×
1081
10000
 −
229207631
1000000000
 x ×
49
2500
 +
229207631
10000000000
(100 −
1081
10000
 −
49
2500
) ÷ (1 +
31
100
 ×
49
2500
)

    The solution of the equation:
        x1≈-146.305976 , keep 6 decimal places
        x2≈-1.215822 , keep 6 decimal places
        x3≈0.087454 , keep 6 decimal places    
    There are 3 solution(s).

解程的详细方法请参阅：《方程的解法》


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