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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 5(x-1)(x-1)+5-5(x-0.25) = 1.25 .
    Question type: Equation
    Solution:Original question:
     5( x − 1)( x − 1) + 5 − 5( x −
1
4
) =
5
4
    Remove the bracket on the left of the equation:
     Left side of the equation = 5 x ( x − 1) − 5 × 1( x − 1) + 5 − 5( x −
1
4
)
                                             = 5 x ( x − 1) − 5( x − 1) + 5 − 5( x −
1
4
)
                                             = 5 x x − 5 x × 1 − 5( x − 1) + 5 − 5( x −
1
4
)
                                             = 5 x x − 5 x − 5( x − 1) + 5 − 5( x −
1
4
)
                                             = 5 x x − 5 x − 5 x + 5 × 1 + 5 − 5( x −
1
4
)
                                             = 5 x x − 5 x − 5 x + 5 + 5 − 5( x −
1
4
)
                                             = 5 x x − 10 x + 10 − 5( x −
1
4
)
                                             = 5 x x − 10 x + 10 − 5 x + 5 ×
1
4
                                             = 5 x x − 10 x + 10 − 5 x +
5
4
                                             = 5 x x − 15 x +
45
4
    The equation is transformed into :
     5 x x − 15 x +
45
4
=
5
4

    After the equation is converted into a general formula, it is converted into:
    ( x - 1 )( x - 2 )=0
    From
        x - 1 = 0
        x - 2 = 0

    it is concluded that::
        x1=1
        x2=2
    
    There are 2 solution(s).


解一元二次方程的详细方法请参阅:《一元二次方程的解法》



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