Mathematics
         
语言:中文    Language:English
On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (40/X十8.5)/(50/X+6.8) = 0.507/0.493 .
    Question type: Equation
    Solution:Original question:
     (40 ÷ X +
17
2
) ÷ (50 ÷ X +
34
5
) =
507
1000
÷
493
1000
     Multiply both sides of the equation by:(50 ÷ X +
34
5
)
     (40 ÷ X +
17
2
) =
507
1000
÷
493
1000
× (50 ÷ X +
34
5
)
    Remove a bracket on the left of the equation::
     40 ÷ X +
17
2
=
507
1000
÷
493
1000
× (50 ÷ X +
34
5
)
    Remove a bracket on the right of the equation::
     40 ÷ X +
17
2
=
507
1000
÷
493
1000
× 50 ÷ X +
507
1000
÷
493
1000
×
34
5
    The equation is reduced to :
     40 ÷ X +
17
2
=
25350
493
÷ X +
1014
145
     Multiply both sides of the equation by: X
     40 +
17
2
X =
25350
493
÷ 1 × 1 +
1014
145
X

    Transposition :
     
17
2
X
1014
145
X =
25350
493
÷ 1 × 140

    Calculate the items on the right of the equation:
     
17
2
X
1014
145
X =
25350
493
40

    Combine the items on the left of the equation:
     
437
290
X =
25350
493
40

    Combine the items on the right of the equation:
     
437
290
X =
5630
493

    The coefficient of the unknown number is reduced to 1 :
      X =
5630
493
÷
437
290
        =
5630
493
×
290
437

    We obtained :
      X =
1632700
215441
    This is the solution of the equation.

    By reducing fraction, we can get:
      X =
56300
7429

    Convert the result to decimal form :
      X = 7.578409



Your problem has not been solved here? Please go to the Hot Problems section!





  New addition:Lenders ToolBox module(Specific location:Math OP > Lenders ToolBox ),welcome。