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On line Solution of Monovariate Equation：
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 2/3*x/(1+1/100)-1/(1+1.15/100)+1/3*x/(1+1/100)-1/(1+1.3/100) = 300 .
    Question type: Equation
    Solution:Original question:
     2 ÷ 3 × x ÷ (1 + 1 ÷ 100) − 1 ÷ (1 +
23
20
 ÷ 100) + 1 ÷ 3 × x ÷ (1 + 1 ÷ 100) − 1 ÷ (1 +
13
10
 ÷ 100) = 300
     Multiply both sides of the equation by:(1 + 1 ÷ 100)
     2 ÷ 3 × x − 1 ÷ (1 +
23
20
 ÷ 100) × (1 + 1 ÷ 100) + 1 ÷ 3 × x ÷ (1 + 1 ÷ 100) × (1 + 1 ÷ 100) − 1 = 300(1 + 1 ÷ 100)
    Remove a bracket on the left of the equation:：
     2 ÷ 3 × x − 1 ÷ (1 +
23
20
 ÷ 100) × 1 − 1 ÷ (1 +
23
20
 ÷ 100) × 1 ÷ 100 + 1 ÷ 3 = 300(1 + 1 ÷ 100)
    Remove a bracket on the right of the equation:：
     2 ÷ 3 × x − 1 ÷ (1 +
23
20
 ÷ 100) × 1 − 1 ÷ (1 +
23
20
 ÷ 100) × 1 ÷ 100 + 1 ÷ 3 = 300 × 1 + 300 × 1 ÷ 100
    The equation is reduced to :
     
2
3
 x − 1 ÷ (1 +
23
20
 ÷ 100) −
1
100
 ÷ (1 +
23
20
 ÷ 100) +
1
3
 x ÷ (1 + 1 ÷ 100) × (1 + 1 ÷ 100) − 1 ÷ (1 +
13
10
 ÷ 100) = 300 + 3
    The equation is reduced to :
     
2
3
 x − 1 ÷ (1 +
23
20
 ÷ 100) −
1
100
 ÷ (1 +
23
20
 ÷ 100) +
1
3
 x ÷ (1 + 1 ÷ 100) × (1 + 1 ÷ 100) − 1 ÷ (1 +
13
10
 ÷ 100) = 303
     Multiply both sides of the equation by:(1 +
23
20
 ÷ 100)
     
2
3
 x (1 +
23
20
 ÷ 100) − 1 −
1
100
 ÷ (1 +
23
20
 ÷ 100) × (1 +
23
20
 ÷ 100) +
1
3
 x ÷ (1 + 1 ÷ 100) × (1 + 1 ÷ 100)(1 +
23
20
 ÷ 100) = 303(1 +
23
20
 ÷ 100)
    Remove a bracket on the left of the equation:
     
2
3
 x × 1 +
2
3
 x ×
23
20
 ÷ 100 − 1 −
1
100
 ÷ (1 +
23
20
 ÷ 100) × (1 +
23
20
 ÷ 100) +
1
3
 = 303(1 +
23
20
 ÷ 100)
    Remove a bracket on the right of the equation:：
     
2
3
 x × 1 +
2
3
 x ×
23
20
 ÷ 100 − 1 −
1
100
 ÷ (1 +
23
20
 ÷ 100) × (1 +
23
20
 ÷ 100) +
1
3
 = 303 × 1 + 303 ×
23
20
 ÷ 100
    The equation is reduced to :
     
2
3
 x +
23
3000
 x − 1 −
1
100
 ÷ (1 +
23
20
 ÷ 100) × (1 +
23
20
 ÷ 100) +
1
3
 x ÷ (1 + 1 ÷ 100) × (1 + 1 ÷ 100) = 303 +
6969
2000
    The equation is reduced to :
     
2023
3000
 x − 1 −
1
100
 ÷ (1 +
23
20
 ÷ 100) × (1 +
23
20
 ÷ 100) +
1
3
 x ÷ (1 + 1 ÷ 100) × (1 + 1 ÷ 100)(1 +
23
20
 ÷ 100) − 1 =
612969
2000
     Multiply both sides of the equation by:(1 +
23
20
 ÷ 100)
     
2023
3000
 x (1 +
23
20
 ÷ 100) − 1(1 +
23
20
 ÷ 100) −
1
100
(1 +
23
20
 ÷ 100) +
1
3
 x ÷ (1 + 1 ÷ 100) × (1 + 1 ÷ 100)(1 +
23
20
 ÷ 100) =
612969
2000
(1 +
23
20
 ÷ 100)
    Remove a bracket on the left of the equation:
     
2023
3000
 x × 1 +
2023
3000
 x ×
23
20
 ÷ 100 − 1(1 +
23
20
 ÷ 100) −
1
100
(1 +
23
20
 ÷ 100) +
1
3
 =
612969
2000
(1 +
23
20
 ÷ 100)
    Remove a bracket on the right of the equation:：
     
2023
3000
 x × 1 +
2023
3000
 x ×
23
20
 ÷ 100 − 1(1 +
23
20
 ÷ 100) −
1
100
(1 +
23
20
 ÷ 100) +
1
3
 =
612969
2000
 × 1 +
612969
2000
 ×
23
20
 ÷ 100
    The equation is reduced to :
     
2023
3000
 x +
46529
6000000
 x − 1(1 +
23
20
 ÷ 100) −
1
100
(1 +
23
20
 ÷ 100) +
1
3
 x ÷ (1 + 1 ÷ 100) × (1 + 1 ÷ 100) =
612969
2000
 +
14098287
4000000

    
        x≈304.995556 , keep 6 decimal places    
    There are 1 solution(s).

解一元一次方程的详细方法请参阅：《一元一次方程的解法》


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