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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (1000+112*x)/5.6+150/(1/6*2*2.8*2.8) = 1.2*(150+55.5*(x-0.5)) .
    Question type: Equation
    Solution:Original question:
     (1000 + 112 x ) ÷
28
5
+ 150 ÷ (1 ÷ 6 × 2 ×
14
5
×
14
5
) =
6
5
(150 +
111
2
( x
1
2
))
     Multiply both sides of the equation by:(1 ÷ 6 × 2 ×
14
5
×
14
5
)
     (1000 + 112 x ) ÷
28
5
× (1 ÷ 6 × 2 ×
14
5
×
14
5
) + 150 =
6
5
(150 +
111
2
( x
1
2
))(1 ÷ 6 × 2 ×
14
5
×
14
5
)
    Remove a bracket on the left of the equation::
     1000 ÷
28
5
× (1 ÷ 6 × 2 ×
14
5
×
14
5
) + 112 x ÷
28
5
× (1 ÷ 6 × 2 ×
14
5
×
14
5
) + 150 =
6
5
(150 +
111
2
( x
1
2
))(1 ÷ 6 × 2 ×
14
5
×
14
5
)
    Remove a bracket on the right of the equation::
     1000 ÷
28
5
× (1 ÷ 6 × 2 ×
14
5
×
14
5
) + 112 x ÷
28
5
× (1 ÷ 6 × 2 ×
14
5
×
14
5
) + 150 =
6
5
× 150(1 ÷ 6 × 2 ×
14
5
×
14
5
) +
6
5
×
111
2
( x
1
2
)(1 ÷ 6 × 2 ×
14
5
×
14
5
)
    The equation is reduced to :
     
1250
7
(1 ÷ 6 × 2 ×
14
5
×
14
5
) + 20 x (1 ÷ 6 × 2 ×
14
5
×
14
5
) + 150 = 180(1 ÷ 6 × 2 ×
14
5
×
14
5
) +
333
5
( x
1
2
)(1 ÷ 6 × 2 ×
14
5
×
14
5
)
    Remove a bracket on the left of the equation:
     
1250
7
× 1 ÷ 6 × 2 ×
14
5
×
14
5
+ 20 x (1 ÷ 6 × 2 ×
14
5
×
14
5
) + 150 = 180(1 ÷ 6 × 2 ×
14
5
×
14
5
) +
333
5
( x
1
2
)(1 ÷ 6 × 2 ×
14
5
×
14
5
)
    Remove a bracket on the right of the equation::
     
1250
7
× 1 ÷ 6 × 2 ×
14
5
×
14
5
+ 20 x (1 ÷ 6 × 2 ×
14
5
×
14
5
) + 150 = 180 × 1 ÷ 6 × 2 ×
14
5
×
14
5
+
333
5
( x
1
2
)(1 ÷ 6 × 2 ×
14
5
×
14
5
)
    The equation is reduced to :
     
1400
3
+ 20 x (1 ÷ 6 × 2 ×
14
5
×
14
5
) + 150 =
2352
5
+
333
5
( x
1
2
)(1 ÷ 6 × 2 ×
14
5
×
14
5
)
    The equation is reduced to :
     
1850
3
+ 20 x (1 ÷ 6 × 2 ×
14
5
×
14
5
) =
2352
5
+
333
5
( x
1
2
)(1 ÷ 6 × 2 ×
14
5
×
14
5
)
    Remove a bracket on the left of the equation:
     
1850
3
+ 20 x × 1 ÷ 6 × 2 ×
14
5
×
14
5
=
2352
5
+
333
5
( x
1
2
)(1 ÷ 6 × 2 ×
14
5
×
14
5
)
    Remove a bracket on the right of the equation::
     
1850
3
+ 20 x × 1 ÷ 6 × 2 ×
14
5
×
14
5
=
2352
5
+
333
5
x (1 ÷ 6 × 2 ×
14
5
×
14
5
)
333
5
×
1
2
(1 ÷ 6 × 2 ×
14
5
×
14
5
)
    The equation is reduced to :
     
1850
3
+
784
15
x =
2352
5
+
333
5
x (1 ÷ 6 × 2 ×
14
5
×
14
5
)
333
10
(1 ÷ 6 × 2 ×
14
5
×
14
5
)
    Remove a bracket on the right of the equation::
     
1850
3
+
784
15
x =
2352
5
+
333
5
x × 1 ÷ 6 × 2 ×
14
5
×
14
5
333
10
(1 ÷ 6 × 2 ×
14
5
×
14
5
)
    The equation is reduced to :
     
1850
3
+
784
15
x =
2352
5
+
21756
125
x
333
10
(1 ÷ 6 × 2 ×
14
5
×
14
5
)
    Remove a bracket on the right of the equation::
     
1850
3
+
784
15
x =
2352
5
+
21756
125
x
333
10
× 1 ÷ 6 × 2 ×
14
5
×
14
5
    The equation is reduced to :
     
1850
3
+
784
15
x =
2352
5
+
21756
125
x
10878
125
    The equation is reduced to :
     
1850
3
+
784
15
x =
47922
125
+
21756
125
x

    Transposition :
     
784
15
x
21756
125
x =
47922
125
1850
3

    Combine the items on the left of the equation:
      -
45668
375
x =
47922
125
1850
3

    Combine the items on the right of the equation:
      -
45668
375
x = -
87484
375

    By shifting the terms and changing the symbols on toth sides of the equation, we obtain :
     
87484
375
=
45668
375
x

    If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :
     
45668
375
x =
87484
375

    The coefficient of the unknown number is reduced to 1 :
      x =
87484
375
÷
45668
375
        =
87484
375
×
375
45668
        = 21871 ×
1
11417

    We obtained :
      x =
21871
11417
    This is the solution of the equation.

    Convert the result to decimal form :
      x = 1.915652



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