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           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation a+0.2a+((0.2a+a)*0.2)+((a+0.2a)+(a+0.2a+((0.2a+a)*0.2))*0.06 ) = 181260 .
    Question type: Equation
    Solution:Original question:
      a +
1
5
a + ((
1
5
a + a ) ×
1
5
) + (( a +
1
5
a ) + ( a +
1
5
a + ((
1
5
a + a ) ×
1
5
)) ×
3
50
) = 181260
     Left side of the equation =
6
5
a + ((
1
5
a + a ) ×
1
5
) + (( a +
1
5
a ) + ( a +
1
5
a + ((
1
5
a + a ) ×
1
5
)) ×
3
50
)
    The equation is transformed into :
     
6
5
a + ((
1
5
a + a ) ×
1
5
) + (( a +
1
5
a ) + ( a +
1
5
a + ((
1
5
a + a ) ×
1
5
)) ×
3
50
) = 181260
    Remove the bracket on the left of the equation:
     Left side of the equation =
6
5
a + (
1
5
a + a ) ×
1
5
+ (( a +
1
5
a ) + ( a +
1
5
a + ((
1
5
a + a ) ×
1
5
)) ×
3
50
)
                                             =
6
5
a +
1
5
a ×
1
5
+ a ×
1
5
+ (( a +
1
5
a ) + ( a +
1
5
a + ((
1
5
a + a ) ×
1
5
)) ×
3
50
)
                                             =
6
5
a +
1
25
a + a ×
1
5
+ (( a +
1
5
a ) + ( a +
1
5
a + ((
1
5
a + a ) ×
1
5
)) ×
3
50
)
                                             =
36
25
a + (( a +
1
5
a ) + ( a +
1
5
a + ((
1
5
a + a ) ×
1
5
)) ×
3
50
)
                                             =
36
25
a + ( a +
1
5
a ) + ( a +
1
5
a + ((
1
5
a + a ) ×
1
5
)) ×
3
50
                                             =
36
25
a + a +
1
5
a + ( a +
1
5
a + ((
1
5
a + a ) ×
1
5
)) ×
3
50
                                             =
66
25
a + ( a +
1
5
a + ((
1
5
a + a ) ×
1
5
)) ×
3
50
                                             =
66
25
a + a ×
3
50
+
1
5
a ×
3
50
+ ((
1
5
a + a ) ×
1
5
) ×
3
50
                                             =
66
25
a + a ×
3
50
+
3
250
a + ((
1
5
a + a ) ×
1
5
) ×
3
50
                                             =
339
125
a + ((
1
5
a + a ) ×
1
5
) ×
3
50
                                             =
339
125
a + (
1
5
a + a ) ×
1
5
×
3
50
                                             =
339
125
a + (
1
5
a + a ) ×
3
250
                                             =
339
125
a +
1
5
a ×
3
250
+ a ×
3
250
                                             =
339
125
a +
3
1250
a + a ×
3
250
                                             =
1704
625
a
    The equation is transformed into :
     
1704
625
a = 181260

    The coefficient of the unknown number is reduced to 1 :
      a = 181260 ÷
1704
625
        = 181260 ×
625
1704
        = 15105 ×
625
142

    We obtained :
      a =
9440625
142
    This is the solution of the equation.

    Convert the result to decimal form :
      a = 66483.274648



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