Mathematics
         
语言:中文    Language:English
On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 3/4(2x-5)+1/6(x+7) = 2/3(x-2) .
    Question type: Equation
    Solution:Original question:
     3 ÷ 4 × (2 x 5) + 1 ÷ 6 × ( x + 7) = 2 ÷ 3 × ( x 2)
     Left side of the equation =
3
4
(2 x 5) +
1
6
( x + 7)
    The equation is transformed into :
     
3
4
(2 x 5) +
1
6
( x + 7) = 2 ÷ 3 × ( x 2)
    Remove the bracket on the left of the equation:
     Left side of the equation =
3
4
× 2 x
3
4
× 5 +
1
6
( x + 7)
                                             =
3
2
x
15
4
+
1
6
( x + 7)
                                             =
3
2
x
15
4
+
1
6
x +
1
6
× 7
                                             =
3
2
x
15
4
+
1
6
x +
7
6
                                             =
5
3
x
31
12
    The equation is transformed into :
     
5
3
x
31
12
= 2 ÷ 3 × ( x 2)
     Right side of the equation =
2
3
( x 2)
    The equation is transformed into :
     
5
3
x
31
12
=
2
3
( x 2)
    Remove the bracket on the right of the equation:
     Right side of the equation =
2
3
x
2
3
× 2
                                               =
2
3
x
4
3
    The equation is transformed into :
     
5
3
x
31
12
=
2
3
x
4
3

    Transposition :
     
5
3
x
2
3
x = -
4
3
+
31
12
    i.e.
      x = -
4
3
+
31
12

    Combine the items on the left of the equation:
      x = -
4
3
+
31
12

    Combine the items on the right of the equation:
      x =
5
4
    This is the solution of the equation.
    This is the solution of the equation.



Your problem has not been solved here? Please go to the Hot Problems section!





  New addition:Lenders ToolBox module(Specific location:Math OP > Lenders ToolBox ),welcome。