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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 1+1/(x-1)+1/(1+1/(1+1/(x-1))) = 0 .
    Question type: Equation
    Solution:Original question:
     1 + 1 ÷ ( x − 1) + 1 ÷ (1 + 1 ÷ (1 + 1 ÷ ( x − 1))) = 0
     Multiply both sides of the equation by:( x − 1)
     1( x − 1) + 1 + 1 ÷ (1 + 1 ÷ (1 + 1 ÷ ( x − 1))) × ( x − 1) = 0
    Remove a bracket on the left of the equation::
     1 x − 1 × 1 + 1 + 1 ÷ (1 + 1 ÷ (1 + 1 ÷ ( x − 1))) × ( x − 1) = 0
    The equation is reduced to :
     1 x − 1 + 1 + 1 ÷ (1 + 1 ÷ (1 + 1 ÷ ( x − 1))) × ( x − 1) = 0
    The equation is reduced to :
     1 x − 0 + 1 ÷ (1 + 1 ÷ (1 + 1 ÷ ( x − 1))) × ( x − 1) = 0
     Multiply both sides of the equation by:(1 + 1 ÷ (1 + 1 ÷ ( x − 1)))
     1 x (1 + 1 ÷ (1 + 1 ÷ ( x − 1))) − 0 + 1( x − 1) = 0
    Remove a bracket on the left of the equation:
     1 x × 1 + 1 x × 1 ÷ (1 + 1 ÷ ( x − 1)) − 0 + 1( x − 1) = 0
    The equation is reduced to :
     1 x + 1 x ÷ (1 + 1 ÷ ( x − 1)) − 0 + 1( x − 1) = 0
     Multiply both sides of the equation by:(1 + 1 ÷ ( x − 1))
     1 x (1 + 1 ÷ ( x − 1)) + 1 x + 1( x − 1)(1 + 1 ÷ ( x − 1)) = 0
    Remove a bracket on the left of the equation:
     1 x × 1 + 1 x × 1 ÷ ( x − 1) + 1 x + 1( x − 1)(1 + 1 ÷ ( x − 1)) = 0
    The equation is reduced to :
     1 x + 1 x ÷ ( x − 1) + 1 x + 1( x − 1)(1 + 1 ÷ ( x − 1)) = 0
    The equation is reduced to :
     2 x + 1 x ÷ ( x − 1) + 1( x − 1)(1 + 1 ÷ ( x − 1)) = 0
     Multiply both sides of the equation by:( x − 1)
     2 x ( x − 1) + 1 x + 1( x − 1)(1 + 1 ÷ ( x − 1))( x − 1) = 0
    Remove a bracket on the left of the equation:
     2 x x − 2 x × 1 + 1 x + 1( x − 1)(1 + 1 ÷ ( x − 1))( x − 1) = 0
    The equation is reduced to :
     2 x x − 2 x + 1 x + 1( x − 1)(1 + 1 ÷ ( x − 1))( x − 1) = 0
    The equation is reduced to :
     2 x x − 1 x + 1( x − 1)(1 + 1 ÷ ( x − 1))( x − 1) = 0
    Remove a bracket on the left of the equation:
     2 x x − 1 x + 1 x (1 + 1 ÷ ( x − 1))( x − 1) − 1 × 1(1 + 1 ÷ ( x − 1)) = 0
    The equation is reduced to :
     2 x x − 1 x + 1 x (1 + 1 ÷ ( x − 1))( x − 1) − 1(1 + 1 ÷ ( x − 1))( x − 1) = 0
    Remove a bracket on the left of the equation:
     2 x x − 1 x + 1 x × 1( x − 1) + 1 x × 1 = 0
    The equation is reduced to :
     2 x x − 1 x + 1 x ( x − 1) + 1 x ÷ ( x − 1) × ( x − 1) = 0
     Multiply both sides of the equation by:( x − 1)
     2 x x ( x − 1) − 1 x ( x − 1) + 1 x ( x − 1)( x − 1) + 1 = 0

    
        x1=
2
3
    
    There are 1 solution(s).


解一元一次方程的详细方法请参阅:《一元一次方程的解法》



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