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On line Solution of Monovariate Equation：
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
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    Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (25-1.5/((1+x)*1.03)-1.5/((1+x)*1.12)*2-1.5/((1+x)*1.21)*3)/(1.5/(1+x)*1.3 ) = 14 .
    Question type: Equation
    Solution:Original question:
     (25 −
3
2
 ÷ ((1 + x ) ×
103
100
) −
3
2
 ÷ ((1 + x ) ×
28
25
) × 2 −
3
2
 ÷ ((1 + x ) ×
121
100
) × 3) ÷ (
3
2
 ÷ (1 + x ) ×
13
10
) = 14
     Multiply both sides of the equation by:(
3
2
 ÷ (1 + x ) ×
13
10
)
     (25 −
3
2
 ÷ ((1 + x ) ×
103
100
) −
3
2
 ÷ ((1 + x ) ×
28
25
) × 2 −
3
2
 ÷ ((1 + x ) ×
121
100
) × 3) = 14(
3
2
 ÷ (1 + x ) ×
13
10
)
    Remove a bracket on the left of the equation:：
     25 −
3
2
 ÷ ((1 + x ) ×
103
100
) −
3
2
 ÷ ((1 + x ) ×
28
25
) × 2 −
3
2
 ÷ ((1 + x ) ×
121
100
) × 3 = 14(
3
2
 ÷ (1 + x ) ×
13
10
)
    Remove a bracket on the right of the equation:：
     25 −
3
2
 ÷ ((1 + x ) ×
103
100
) −
3
2
 ÷ ((1 + x ) ×
28
25
) × 2 −
3
2
 ÷ ((1 + x ) ×
121
100
) × 3 = 14 ×
3
2
 ÷ (1 + x ) ×
13
10
    The equation is reduced to :
     25 −
3
2
 ÷ ((1 + x ) ×
103
100
) − 3 ÷ ((1 + x ) ×
28
25
) −
9
2
 ÷ ((1 + x ) ×
121
100
) =
273
10
 ÷ (1 + x )
     Multiply both sides of the equation by:((1 + x ) ×
103
100
) ,  (1 + x )
     25((1 + x ) ×
103
100
)(1 + x ) −
3
2
(1 + x ) − 3 ÷ ((1 + x ) ×
28
25
) × ((1 + x ) ×
103
100
)(1 + x ) −
9
2
 ÷ ((1 + x ) ×
121
100
) × ((1 + x ) ×
103
100
) =
273
10
((1 + x ) ×
103
100
)
    Remove a bracket on the left of the equation:
     25(1 + x ) ×
103
100
(1 + x ) −
3
2
(1 + x ) − 3 ÷ ((1 + x ) ×
28
25
) × ((1 + x ) ×
103
100
)(1 + x ) −
9
2
 ÷ ((1 + x ) ×
121
100
) =
273
10
((1 + x ) ×
103
100
)
    Remove a bracket on the right of the equation:：
     25(1 + x ) ×
103
100
(1 + x ) −
3
2
(1 + x ) − 3 ÷ ((1 + x ) ×
28
25
) × ((1 + x ) ×
103
100
)(1 + x ) −
9
2
 ÷ ((1 + x ) ×
121
100
) =
273
10
(1 + x ) ×
103
100
    The equation is reduced to :
     
103
4
(1 + x )(1 + x ) −
3
2
(1 + x ) − 3 ÷ ((1 + x ) ×
28
25
) × ((1 + x ) ×
103
100
)(1 + x ) −
9
2
 ÷ ((1 + x ) ×
121
100
) × ((1 + x ) ×
103
100
) =
28119
1000
(1 + x )
     Multiply both sides of the equation by:((1 + x ) ×
28
25
)
     
103
4
(1 + x )(1 + x )((1 + x ) ×
28
25
) −
3
2
(1 + x )((1 + x ) ×
28
25
) − 3((1 + x ) ×
103
100
)(1 + x ) −
9
2
 ÷ ((1 + x ) ×
121
100
) =
28119
1000
(1 + x )((1 + x ) ×
28
25
)
    Remove a bracket on the left of the equation:
     
103
4
 × 1(1 + x )((1 + x ) ×
28
25
) +
103
4
 x (1 + x )((1 + x ) ×
28
25
) −
3
2
(1 + x )((1 + x ) ×
28
25
) − 3 =
28119
1000
(1 + x )((1 + x ) ×
28
25
)
    Remove a bracket on the right of the equation:：
     
103
4
 × 1(1 + x )((1 + x ) ×
28
25
) +
103
4
 x (1 + x )((1 + x ) ×
28
25
) −
3
2
(1 + x )((1 + x ) ×
28
25
) − 3 =
28119
1000
 × 1((1 + x ) ×
28
25
) +
28119
1000
 x ((1 + x ) ×
28
25
)
    The equation is reduced to :
     
103
4
(1 + x )((1 + x ) ×
28
25
) +
103
4
 x (1 + x )((1 + x ) ×
28
25
) −
3
2
(1 + x )((1 + x ) ×
28
25
) − 3((1 + x ) ×
103
100
) =
28119
1000
((1 + x ) ×
28
25
) +
28119
1000
 x ((1 + x ) ×
28
25
)
     Multiply both sides of the equation by:((1 + x ) ×
121
100
)
     
103
4
(1 + x )((1 + x ) ×
28
25
)((1 + x ) ×
121
100
) +
103
4
 x (1 + x )((1 + x ) ×
28
25
)((1 + x ) ×
121
100
) −
3
2
(1 + x )((1 + x ) ×
28
25
) =
28119
1000
((1 + x ) ×
28
25
)((1 + x ) ×
121
100
) +
28119
1000
 x ((1 + x ) ×
28
25
)((1 + x ) ×
121
100
)
    Remove a bracket on the left of the equation:
     
103
4
 × 1((1 + x ) ×
28
25
)((1 + x ) ×
121
100
) +
103
4
 x ((1 + x ) ×
28
25
)((1 + x ) ×
121
100
) +
103
4
 x (1 + x )((1 + x ) ×
28
25
) =
28119
1000
((1 + x ) ×
28
25
)((1 + x ) ×
121
100
) +
28119
1000
 x ((1 + x ) ×
28
25
)((1 + x ) ×
121
100
)
    Remove a bracket on the right of the equation:：
     
103
4
 × 1((1 + x ) ×
28
25
)((1 + x ) ×
121
100
) +
103
4
 x ((1 + x ) ×
28
25
)((1 + x ) ×
121
100
) +
103
4
 x (1 + x )((1 + x ) ×
28
25
) =
28119
1000
(1 + x ) ×
28
25
((1 + x ) ×
121
100
) +
28119
1000
 x ((1 + x ) ×
28
25
)((1 + x ) ×
121
100
)
    The equation is reduced to :
     
103
4
((1 + x ) ×
28
25
)((1 + x ) ×
121
100
) +
103
4
 x ((1 + x ) ×
28
25
)((1 + x ) ×
121
100
) +
103
4
 x (1 + x )((1 + x ) ×
28
25
)((1 + x ) ×
121
100
) =
196833
6250
(1 + x )((1 + x ) ×
121
100
) +
28119
1000
 x ((1 + x ) ×
28
25
)((1 + x ) ×
121
100
)
    Remove a bracket on the left of the equation:
     
103
4
(1 + x ) ×
28
25
((1 + x ) ×
121
100
) +
103
4
 x ((1 + x ) ×
28
25
)((1 + x ) ×
121
100
) +
103
4
 x (1 + x )((1 + x ) ×
28
25
) =
196833
6250
(1 + x )((1 + x ) ×
121
100
) +
28119
1000
 x ((1 + x ) ×
28
25
)((1 + x ) ×
121
100
)
    Remove a bracket on the right of the equation:：
     
103
4
(1 + x ) ×
28
25
((1 + x ) ×
121
100
) +
103
4
 x ((1 + x ) ×
28
25
)((1 + x ) ×
121
100
) +
103
4
 x (1 + x )((1 + x ) ×
28
25
) =
196833
6250
 × 1((1 + x ) ×
121
100
) +
196833
6250
 x ((1 + x ) ×
121
100
) +
28119
1000
 x ((1 + x ) ×
28
25
)((1 + x ) ×
121
100
)
    The equation is reduced to :
     
721
25
(1 + x )((1 + x ) ×
121
100
) +
103
4
 x ((1 + x ) ×
28
25
)((1 + x ) ×
121
100
) +
103
4
 x (1 + x )((1 + x ) ×
28
25
)((1 + x ) ×
121
100
) =
196833
6250
((1 + x ) ×
121
100
) +
196833
6250
 x ((1 + x ) ×
121
100
) +
28119
1000
 x ((1 + x ) ×
28
25
)((1 + x ) ×
121
100
)
    Remove a bracket on the left of the equation:
     
721
25
 × 1((1 + x ) ×
121
100
) +
721
25
 x ((1 + x ) ×
121
100
) +
103
4
 x ((1 + x ) ×
28
25
)((1 + x ) ×
121
100
) +
103
4
 x =
196833
6250
((1 + x ) ×
121
100
) +
196833
6250
 x ((1 + x ) ×
121
100
) +
28119
1000
 x ((1 + x ) ×
28
25
)((1 + x ) ×
121
100
)

    
        x≈0.406156 , keep 6 decimal places    
    There are 1 solution(s).

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