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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (P-10)(160-P)+(P-10)(65-0.5P) = 0 .
    Question type: Equation
    Solution:Original question:
     ( P 10)(160 P ) + ( P 10)(65
1
2
P ) = 0
    Remove the bracket on the left of the equation:
     Left side of the equation = P (160 P )10(160 P ) + ( P 10)(65
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2
P )
                                             = P × 160 P P 10(160 P ) + ( P 10)(65
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P )
                                             = 160 P P P 10 × 160 + 10 P + ( P 10)(65
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2
P )
                                             = 160 P P P 1600 + 10 P + ( P 10)(65
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2
P )
                                             = 170 P P P 1600 + ( P 10)(65
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2
P )
                                             = 170 P P P 1600 + P (65
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P )10(65
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2
P )
                                             = 170 P P P 1600 + P × 65 P ×
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2
P 10(65
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P )
                                             = 235 P P P 1600 P ×
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2
P 10(65
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2
P )
                                             = 235 P P P 1600 P ×
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2
P 10 × 65 + 10 ×
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2
                                             = 235 P P P 1600 P ×
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2
P 650 + 5 P
                                             = 240 P P P 2250 P ×
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2
P
    The equation is transformed into :
     240 P P P 2250 P ×
1
2
P = 0

    After the equation is converted into a general formula, it is converted into:
    ( P - 10 )( P - 150 )=0
    From
        P - 10 = 0
        P - 150 = 0

    it is concluded that::
        P1=10
        P2=150
    
    There are 2 solution(s).


解一元二次方程的详细方法请参阅:《一元二次方程的解法》



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