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On line Solution of Monovariate Equation：
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation （X-600*12%）*（1-30%）/（100+50） = （X-1350*12%）*（1-30%）/100 .
    Question type: Equation
    Solution:Original question:
     ( X − 600 ×
12
100
)(1 −
30
100
) ÷ (100 + 50) = ( X − 1350 ×
12
100
)(1 −
30
100
) ÷ 100
     Multiply both sides of the equation by:(100 + 50)
     ( X − 600 ×
12
100
)(1 −
30
100
) = ( X − 1350 ×
12
100
)(1 −
30
100
) ÷ 100 × (100 + 50)
    Remove a bracket on the left of the equation:：
      X (1 −
30
100
) − 600 ×
12
100
(1 −
30
100
) = ( X − 1350 ×
12
100
)(1 −
30
100
) ÷ 100 × (100 + 50)
    Remove a bracket on the right of the equation:：
      X (1 −
30
100
) − 600 ×
12
100
(1 −
30
100
) = X (1 −
30
100
) ÷ 100 × (100 + 50) − 1350 ×
12
100
(1 −
30
100
) ÷ 100 × (100 + 50)
    The equation is reduced to :
      X (1 −
30
100
) − 72(1 −
30
100
) = X (1 −
30
100
) ×
1
100
(100 + 50) −
81
50
(1 −
30
100
)(100 + 50)
    Remove a bracket on the left of the equation:
      X × 1 − X ×
30
100
 − 72(1 −
30
100
) = X (1 −
30
100
) ×
1
100
(100 + 50) −
81
50
(1 −
30
100
)(100 + 50)
    Remove a bracket on the right of the equation:：
      X × 1 − X ×
30
100
 − 72(1 −
30
100
) = X × 1 ×
1
100
(100 + 50) − X ×
30
100
 ×
1
100
(100 + 50) −
81
50
(1 −
30
100
)(100 + 50)
    The equation is reduced to :
      X × 1 − X ×
30
100
 − 72(1 −
30
100
) = X ×
1
100
(100 + 50) − X ×
3
1000
(100 + 50) −
81
50
(1 −
30
100
)(100 + 50)
    The equation is reduced to :
     
7
10
 X − 72(1 −
30
100
) = X ×
1
100
(100 + 50) − X ×
3
1000
(100 + 50) −
81
50
(1 −
30
100
)(100 + 50)
    Remove a bracket on the left of the equation:
     
7
10
 X − 72 × 1 + 72 ×
30
100
 = X ×
1
100
(100 + 50) − X ×
3
1000
(100 + 50) −
81
50
(1 −
30
100
)(100 + 50)
    Remove a bracket on the right of the equation:：
     
7
10
 X − 72 × 1 + 72 ×
30
100
 = X ×
1
100
 × 100 + X ×
1
100
 × 50 − X ×
3
1000
(100 + 50) −
81
50
(1 −
30
100
)(100 + 50)
    The equation is reduced to :
     
7
10
 X − 72 +
108
5
 = X × 1 + X ×
1
2
 − X ×
3
1000
(100 + 50) −
81
50
(1 −
30
100
)(100 + 50)
    The equation is reduced to :
     
7
10
 X −
252
5
 =
3
2
 X − X ×
3
1000
(100 + 50) −
81
50
(1 −
30
100
)(100 + 50)
    Remove a bracket on the right of the equation:：
     
7
10
 X −
252
5
 =
3
2
 X − X ×
3
1000
 × 100 − X ×
3
1000
 × 50 −
81
50
(1 −
30
100
)(100 + 50)
    The equation is reduced to :
     
7
10
 X −
252
5
 =
3
2
 X − X ×
3
10
 − X ×
3
20
 −
81
50
(1 −
30
100
)(100 + 50)
    The equation is reduced to :
     
7
10
 X −
252
5
 =
21
20
 X −
81
50
(1 −
30
100
)(100 + 50)
    Remove a bracket on the right of the equation:：
     
7
10
 X −
252
5
 =
21
20
 X −
81
50
 × 1(100 + 50) +
81
50
 ×
30
100
(100 + 50)
    The equation is reduced to :
     
7
10
 X −
252
5
 =
21
20
 X −
81
50
(100 + 50) +
243
500
(100 + 50)
    Remove a bracket on the right of the equation:：
     
7
10
 X −
252
5
 =
21
20
 X −
81
50
 × 100 −
81
50
 × 50 +
243
500
(100 + 50)
    The equation is reduced to :
     
7
10
 X −
252
5
 =
21
20
 X − 162 − 81 +
243
500
(100 + 50)
    The equation is reduced to :
     
7
10
 X −
252
5
 =
21
20
 X − 243 +
243
500
(100 + 50)
    Remove a bracket on the right of the equation:：
     
7
10
 X −
252
5
 =
21
20
 X − 243 +
243
500
 × 100 +
243
500
 × 50
    The equation is reduced to :
     
7
10
 X −
252
5
 =
21
20
 X − 243 +
243
5
 +
243
10
    The equation is reduced to :
     
7
10
 X −
252
5
 =
21
20
 X −
1701
10

    Transposition :
     
7
10
 X −
21
20
 X = -
1701
10
 +
252
5

    Combine the items on the left of the equation:
      -
7
20
 X = -
1701
10
 +
252
5

    Combine the items on the right of the equation:
      -
7
20
 X = -
1197
10

    By shifting the terms and changing the symbols on toth sides of the equation, we obtain :
     
1197
10
 =
7
20
 X

    If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :
     
7
20
 X =
1197
10

    The coefficient of the unknown number is reduced to 1 :
      X =
1197
10
 ÷
7
20
        =
1197
10
 ×
20
7
        = 171 × 2

    We obtained :
      X = 342
    This is the solution of the equation.



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