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On line Solution of Monovariate Equation：
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 1-（1+X）（1+X）（1+X）（1+X）（1+X）（1+X）（1+X）（1+X）（1+X）（1+X）（1+X）（1+X） = 11.72X .
    Question type: Equation
    Solution:Original question:
     1 − (1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X ) =
293
25
 X
    Remove the bracket on the left of the equation:
     Left side of the equation = 1 − 1(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )
                                             = 1 − 1 × 1(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )
                                             = 1 − 1(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )
                                             = 1 − 1 × 1(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )
                                             = 1 − 1(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X ) − 1
                                             = 1 − 1 × 1(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X ) − 1
                                             = 1 − 1(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X ) − 1 X
                                             = 1 − 1 × 1(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X ) − 1 X
                                             = 1 − 1(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X ) − 1 X (1 + X )
                                             = 1 − 1 × 1(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X ) − 1 X (1 + X )
                                             = 1 − 1(1 + X )(1 + X )(1 + X )(1 + X )(1 + X )(1 + X ) − 1 X (1 + X )(1 + X )
                                             = 1 − 1 × 1(1 + X )(1 + X )(1 + X )(1 + X )(1 + X ) − 1 X (1 + X )(1 + X )
                                             = 1 − 1(1 + X )(1 + X )(1 + X )(1 + X )(1 + X ) − 1 X (1 + X )(1 + X )(1 + X )
                                             = 1 − 1 × 1(1 + X )(1 + X )(1 + X )(1 + X ) − 1 X (1 + X )(1 + X )(1 + X )
                                             = 1 − 1(1 + X )(1 + X )(1 + X )(1 + X ) − 1 X (1 + X )(1 + X )(1 + X )(1 + X )
                                             = 1 − 1 × 1(1 + X )(1 + X )(1 + X ) − 1 X (1 + X )(1 + X )(1 + X ) − 1
                                             = 1 − 1(1 + X )(1 + X )(1 + X ) − 1 X (1 + X )(1 + X )(1 + X ) − 1 X
                                             = 1 − 1 × 1(1 + X )(1 + X ) − 1 X (1 + X )(1 + X ) − 1 X (1 + X )
                                             = 1 − 1(1 + X )(1 + X ) − 1 X (1 + X )(1 + X ) − 1 X (1 + X )(1 + X )
                                             = 1 − 1 × 1(1 + X ) − 1 X (1 + X ) − 1 X (1 + X )(1 + X ) − 1
                                             = 1 − 1(1 + X ) − 1 X (1 + X ) − 1 X (1 + X )(1 + X ) − 1 X
                                             = 1 − 1 × 1 − 1 X − 1 X (1 + X ) − 1 X (1 + X )(1 + X )
                                             = 1 − 1 − 1 X − 1 X (1 + X ) − 1 X (1 + X )(1 + X ) − 1
                                             = 0 − 1 X − 1 X (1 + X ) − 1 X (1 + X )(1 + X ) − 1 X
                                             = 0 − 1 X − 1 X × 1 − 1 X X − 1 X (1 + X )

    After the equation is converted into a general formula, there is a common factor:
    ( X - 0 )
    From
        X - 0 = 0
    it is concluded that:：
        X1=0

    Solutions that cannot be obtained by factorization:
        X2≈-2.320853 , keep 6 decimal places    
    There are 2 solution(s).

解程的详细方法请参阅：《方程的解法》


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