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On line Solution of Monovariate Equation：
Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
It supports equations that contain mathematical functions.
Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
It supports equations that contain mathematical functions.
Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation （x-21）/3+（x-17）/7+（x-13）/11 = 3 .
Question type: Equation
Solution:Original question:
Remove the bracket on the left of the equation:
The equation is transformed into :
Transposition :
Combine the items on the right of the equation:
The coefficient of the unknown number is reduced to 1 :
We obtained :
This is the solution of the equation.
By reducing fraction, we can get:
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation （x-21）/3+（x-17）/7+（x-13）/11 = 3 .
Question type: Equation
Solution:Original question:
| ( | x | − | 21 | ) | ÷ | 3 | + | ( | x | − | 17 | ) | ÷ | 7 | + | ( | x | − | 13 | ) | ÷ | 11 | = | 3 |
| Left side of the equation = | x | × | 1 3 | − | 21 | × | 1 3 | + | ( | x | − | 17 | ) | × | 1 7 | + | ( | x | − | 13 | ) | × | 1 11 |
| = | x | × | 1 3 | − | 7 | + | ( | x | − | 17 | ) | × | 1 7 | + | ( | x | − | 13 | ) | × | 1 11 |
| = | 1 3 | x | − | 7 | + | x | × | 1 7 | − | 17 | × | 1 7 | + | ( | x | − | 13 | ) | × | 1 11 |
| = | 1 3 | x | − | 7 | + | x | × | 1 7 | − | 17 7 | + | ( | x | − | 13 | ) | × | 1 11 |
| = | 10 21 | x | − | 66 7 | + | ( | x | − | 13 | ) | × | 1 11 |
| = | 10 21 | x | − | 66 7 | + | x | × | 1 11 | − | 13 | × | 1 11 |
| = | 10 21 | x | − | 66 7 | + | x | × | 1 11 | − | 13 11 |
| = | 131 231 | x | − | 817 77 |
131 231 | x | − | 817 77 | = | 3 |
Transposition :
131 231 | x | = | 3 | + | 817 77 |
Combine the items on the right of the equation:
131 231 | x | = | 1048 77 |
The coefficient of the unknown number is reduced to 1 :
| x | = | 1048 77 | ÷ | 131 231 |
| = | 1048 77 | × | 231 131 |
| = | 1048 | × | 3 131 |
We obtained :
| x | = | 3144 131 |
By reducing fraction, we can get:
| x | = | 24 |