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规定一种运算$*$,有$a*b=a-b+a×b$。如果$9*x=41$,求$x$的值。
解:
由定义可知: $$ 9*x=9-x+9\times x $$ 又因为 $$ 9*x=41 $$ 所以 $$ \begin{align} &9-x+9\times x=41\\ =>\ &8x=32\\ =>\ &x=4 \end{align} $$ 所以,所求的$x$的值为:
$x=4$
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