Hot issues：
This module collects the frequently encountered and difficult problems for reference only.
This module collects the frequently encountered and difficult problems for reference only.
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一辆汽车在平直公路上匀速行驶$160m$。在此过程中，汽车牵引力做功$8.0 \times 10^4J$。这辆汽车的牵引力有多 大?
在这里，牵引力做的功$W=8.0 \times 10^4J$，牵引力方向上的位移$s=160m$，牵引力为$F$，则：
由功的计算公式$W=Fs$得： \begin{align} F=& \frac Ws\\ =& \frac{8.0 \times 10^4J}{160m}\\ =& 500N \end{align}
所以，这两汽车的牵引力为$500N$