Mathematics
         
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Get the inverse matrix:
    Enter an invertible matrix, with each element separated by a comma and each row ending with a semicolon.
    Note that mathematical functions and variables are not supported.
    Current location:Linear algebra >Inverse matrix >History of inverse matrices >Answer

$$\begin{aligned}&\\ \color{black}{Calcu}&\color{black}{late\ the\ inverse\ matrix\ of\ } \ \ \begin{pmatrix} &1\ &0\ &0\ &0\ &0\ &0\ \\ &1\ &1\ &0\ &0\ &0\ &0\ \\ &1\ &2\ &1\ &0\ &0\ &0\ \\ &1\ &3\ &3\ &1\ &0\ &0\ \\ &1\ &4\ &6\ &4\ &1\ &0\ \\ &1\ &5\ &10\ &10\ &5\ &1\ \end{pmatrix}\color{black}{\ .}\\ \\Solu&tion:\\ &\begin{pmatrix} &1\ &0\ &0\ &0\ &0\ &0\ \\ &1\ &1\ &0\ &0\ &0\ &0\ \\ &1\ &2\ &1\ &0\ &0\ &0\ \\ &1\ &3\ &3\ &1\ &0\ &0\ \\ &1\ &4\ &6\ &4\ &1\ &0\ \\ &1\ &5\ &10\ &10\ &5\ &1\ \end{pmatrix}\\\\&\color{grey}{Using\ the\ elementary\ transformation\ of\ the\ matrix\ to\ find\ the\ inverse\ matrix:}\\&\left (\begin{array} {ccccccc | cccccc} &1\ &0\ &0\ &0\ &0\ &0\ &1\ &0\ &0\ &0\ &0\ &0\ \\ &1\ &1\ &0\ &0\ &0\ &0\ &0\ &1\ &0\ &0\ &0\ &0\ \\ &1\ &2\ &1\ &0\ &0\ &0\ &0\ &0\ &1\ &0\ &0\ &0\ \\ &1\ &3\ &3\ &1\ &0\ &0\ &0\ &0\ &0\ &1\ &0\ &0\ \\ &1\ &4\ &6\ &4\ &1\ &0\ &0\ &0\ &0\ &0\ &1\ &0\ \\ &1\ &5\ &10\ &10\ &5\ &1\ &0\ &0\ &0\ &0\ &0\ &1\ \\\end{array} \right )\\\\&\color{grey}{Transfprming\ a\ known\ matrix\ into\ an\ upper\ triangular\ matrix :}\\\\->\ \ &\left (\begin{array} {ccccccc | cccccc} &1\ &0\ &0\ &0\ &0\ &0\ &1\ &0\ &0\ &0\ &0\ &0\ \\ &0\ &1\ &0\ &0\ &0\ &0\ &-1\ &1\ &0\ &0\ &0\ &0\ \\ &0\ &2\ &1\ &0\ &0\ &0\ &-1\ &0\ &1\ &0\ &0\ &0\ \\ &0\ &3\ &3\ &1\ &0\ &0\ &-1\ &0\ &0\ &1\ &0\ &0\ \\ &0\ &4\ &6\ &4\ &1\ &0\ &-1\ &0\ &0\ &0\ &1\ &0\ \\ &0\ &5\ &10\ &10\ &5\ &1\ &-1\ &0\ &0\ &0\ &0\ &1\ \\\end{array} \right )\\\\->\ \ &\left (\begin{array} {ccccccc | cccccc} &1\ &0\ &0\ &0\ &0\ &0\ &1\ &0\ &0\ &0\ &0\ &0\ \\ &0\ &1\ &0\ &0\ &0\ &0\ &-1\ &1\ &0\ &0\ &0\ &0\ \\ &0\ &0\ &1\ &0\ &0\ &0\ &1\ &-2\ &1\ &0\ &0\ &0\ \\ &0\ &0\ &3\ &1\ &0\ &0\ &2\ &-3\ &0\ &1\ &0\ &0\ \\ &0\ &0\ &6\ &4\ &1\ &0\ &3\ &-4\ &0\ &0\ &1\ &0\ \\ &0\ &0\ &10\ &10\ &5\ &1\ &4\ &-5\ &0\ &0\ &0\ &1\ \\\end{array} \right )\\\\->\ \ &\left (\begin{array} {ccccccc | cccccc} &1\ &0\ &0\ &0\ &0\ &0\ &1\ &0\ &0\ &0\ &0\ &0\ \\ &0\ &1\ &0\ &0\ &0\ &0\ &-1\ &1\ &0\ &0\ &0\ &0\ \\ &0\ &0\ &1\ &0\ &0\ &0\ &1\ &-2\ &1\ &0\ &0\ &0\ \\ &0\ &0\ &0\ &1\ &0\ &0\ &-1\ &3\ &-3\ &1\ &0\ &0\ \\ &0\ &0\ &0\ &4\ &1\ &0\ &-3\ &8\ &-6\ &0\ &1\ &0\ \\ &0\ &0\ &0\ &10\ &5\ &1\ &-6\ &15\ &-10\ &0\ &0\ &1\ \\\end{array} \right )\\\\->\ \ &\left (\begin{array} {ccccccc | cccccc} &1\ &0\ &0\ &0\ &0\ &0\ &1\ &0\ &0\ &0\ &0\ &0\ \\ &0\ &1\ &0\ &0\ &0\ &0\ &-1\ &1\ &0\ &0\ &0\ &0\ \\ &0\ &0\ &1\ &0\ &0\ &0\ &1\ &-2\ &1\ &0\ &0\ &0\ \\ &0\ &0\ &0\ &1\ &0\ &0\ &-1\ &3\ &-3\ &1\ &0\ &0\ \\ &0\ &0\ &0\ &0\ &1\ &0\ &1\ &-4\ &6\ &-4\ &1\ &0\ \\ &0\ &0\ &0\ &0\ &5\ &1\ &4\ &-15\ &20\ &-10\ &0\ &1\ \\\end{array} \right )\\\\->\ \ &\left (\begin{array} {ccccccc | cccccc} &1\ &0\ &0\ &0\ &0\ &0\ &1\ &0\ &0\ &0\ &0\ &0\ \\ &0\ &1\ &0\ &0\ &0\ &0\ &-1\ &1\ &0\ &0\ &0\ &0\ \\ &0\ &0\ &1\ &0\ &0\ &0\ &1\ &-2\ &1\ &0\ &0\ &0\ \\ &0\ &0\ &0\ &1\ &0\ &0\ &-1\ &3\ &-3\ &1\ &0\ &0\ \\ &0\ &0\ &0\ &0\ &1\ &0\ &1\ &-4\ &6\ &-4\ &1\ &0\ \\ &0\ &0\ &0\ &0\ &0\ &1\ &-1\ &5\ &-10\ &10\ &-5\ &1\ \\\end{array} \right )\\\\&\color{grey}{The\ inverse\ matrix\ obtained\ is\ : }\\&\begin{pmatrix} &1\ &0\ &0\ &0\ &0\ &0\ \\ &-1\ &1\ &0\ &0\ &0\ &0\ \\ &1\ &-2\ &1\ &0\ &0\ &0\ \\ &-1\ &3\ &-3\ &1\ &0\ &0\ \\ &1\ &-4\ &6\ &-4\ &1\ &0\ \\ &-1\ &5\ &-10\ &10\ &-5\ &1\ \end{pmatrix}\end{aligned}$$

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Elementary transformations of matrices:


Definition:Applying the following three transformations to the rows (columns) of a matrix becomes the elementary transformation of the matrix
(1) Swap the positions of two rows (columns) in a matrix;
(2) Using non-zero constants λ Multiply a certain row (column) of a matrix;
(3) Convert a row (column) of a matrix γ Multiply to another row (column) of the matrix.



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