Mathematics
         
语言:中文    Language:English
Get the inverse matrix:
    Enter an invertible matrix, with each element separated by a comma and each row ending with a semicolon.
    Note that mathematical functions and variables are not supported.
    Current location:Linear algebra >Inverse matrix >History of inverse matrices >Answer

$$\begin{aligned}&\\ \color{black}{Calcu}&\color{black}{late\ the\ inverse\ matrix\ of\ } \ \ \begin{pmatrix} &1\ &2\ &3\ &4\ \\ &2\ &3\ &1\ &2\ \\ &1\ &1\ &1\ &-1\ \\ &1\ &0\ &-2\ &-6\ \end{pmatrix}\color{black}{\ .}\\ \\Solu&tion:\\ &\begin{pmatrix} &1\ &2\ &3\ &4\ \\ &2\ &3\ &1\ &2\ \\ &1\ &1\ &1\ &-1\ \\ &1\ &0\ &-2\ &-6\ \end{pmatrix}\\\\&\color{grey}{Using\ the\ elementary\ transformation\ of\ the\ matrix\ to\ find\ the\ inverse\ matrix:}\\&\left (\begin{array} {ccccc | cccc} &1\ &2\ &3\ &4\ &1\ &0\ &0\ &0\ \\ &2\ &3\ &1\ &2\ &0\ &1\ &0\ &0\ \\ &1\ &1\ &1\ &-1\ &0\ &0\ &1\ &0\ \\ &1\ &0\ &-2\ &-6\ &0\ &0\ &0\ &1\ \\\end{array} \right )\\\\&\color{grey}{Transfprming\ a\ known\ matrix\ into\ an\ upper\ triangular\ matrix :}\\\\->\ \ &\left (\begin{array} {ccccc | cccc} &1\ &2\ &3\ &4\ &1\ &0\ &0\ &0\ \\ &0\ &-1\ &-5\ &-6\ &-2\ &1\ &0\ &0\ \\ &0\ &-1\ &-2\ &-5\ &-1\ &0\ &1\ &0\ \\ &0\ &-2\ &-5\ &-10\ &-1\ &0\ &0\ &1\ \\\end{array} \right )\\\\->\ \ &\left (\begin{array} {ccccc | cccc} &1\ &2\ &3\ &4\ &1\ &0\ &0\ &0\ \\ &0\ &-1\ &-5\ &-6\ &-2\ &1\ &0\ &0\ \\ &0\ &0\ &3\ &1\ &1\ &-1\ &1\ &0\ \\ &0\ &0\ &5\ &2\ &3\ &-2\ &0\ &1\ \\\end{array} \right )\\\\->\ \ &\left (\begin{array} {ccccc | cccc} &1\ &2\ &3\ &4\ &1\ &0\ &0\ &0\ \\ &0\ &-1\ &-5\ &-6\ &-2\ &1\ &0\ &0\ \\ &0\ &0\ &3\ &1\ &1\ &-1\ &1\ &0\ \\ &0\ &0\ &0\ &\frac{1}{3}\ &\frac{4}{3}\ &-\frac{1}{3}\ &-\frac{5}{3}\ &1\ \\\end{array} \right )\\\\&\color{grey}{Convert\ elements\ above\ the\ diagonal\ to\ 0}\\\\->\ \ &\left (\begin{array} {ccccc | cccc} &1\ &2\ &3\ &0\ &-15\ &4\ &20\ &-12\ \\ &0\ &-1\ &-5\ &0\ &22\ &-5\ &-30\ &18\ \\ &0\ &0\ &3\ &0\ &-3\ &0\ &6\ &-3\ \\ &0\ &0\ &0\ &\frac{1}{3}\ &\frac{4}{3}\ &-\frac{1}{3}\ &-\frac{5}{3}\ &1\ \\\end{array} \right )\\\\->\ \ &\left (\begin{array} {ccccc | cccc} &1\ &2\ &0\ &0\ &-12\ &4\ &14\ &-9\ \\ &0\ &-1\ &0\ &0\ &17\ &-5\ &-20\ &13\ \\ &0\ &0\ &3\ &0\ &-3\ &0\ &6\ &-3\ \\ &0\ &0\ &0\ &\frac{1}{3}\ &\frac{4}{3}\ &-\frac{1}{3}\ &-\frac{5}{3}\ &1\ \\\end{array} \right )\\\\->\ \ &\left (\begin{array} {ccccc | cccc} &1\ &0\ &0\ &0\ &22\ &-6\ &-26\ &17\ \\ &0\ &-1\ &0\ &0\ &17\ &-5\ &-20\ &13\ \\ &0\ &0\ &3\ &0\ &-3\ &0\ &6\ &-3\ \\ &0\ &0\ &0\ &\frac{1}{3}\ &\frac{4}{3}\ &-\frac{1}{3}\ &-\frac{5}{3}\ &1\ \\\end{array} \right )\\\\&\color{grey}{Convert\ elements\ on\ the\ main\ diagonal\ to\ 1}\\\\->\ \ &\left (\begin{array} {ccccc | cccc} &1\ &0\ &0\ &0\ &22\ &-6\ &-26\ &17\ \\ &0\ &1\ &0\ &0\ &-17\ &5\ &20\ &-13\ \\ &0\ &0\ &3\ &0\ &-3\ &0\ &6\ &-3\ \\ &0\ &0\ &0\ &\frac{1}{3}\ &\frac{4}{3}\ &-\frac{1}{3}\ &-\frac{5}{3}\ &1\ \\\end{array} \right )\\\\->\ \ &\left (\begin{array} {ccccc | cccc} &1\ &0\ &0\ &0\ &22\ &-6\ &-26\ &17\ \\ &0\ &1\ &0\ &0\ &-17\ &5\ &20\ &-13\ \\ &0\ &0\ &1\ &0\ &-1\ &0\ &2\ &-1\ \\ &0\ &0\ &0\ &\frac{1}{3}\ &\frac{4}{3}\ &-\frac{1}{3}\ &-\frac{5}{3}\ &1\ \\\end{array} \right )\\\\->\ \ &\left (\begin{array} {ccccc | cccc} &1\ &0\ &0\ &0\ &22\ &-6\ &-26\ &17\ \\ &0\ &1\ &0\ &0\ &-17\ &5\ &20\ &-13\ \\ &0\ &0\ &1\ &0\ &-1\ &0\ &2\ &-1\ \\ &0\ &0\ &0\ &1\ &4\ &-1\ &-5\ &3\ \\\end{array} \right )\\\\&\color{grey}{The\ inverse\ matrix\ obtained\ is\ : }\\&\begin{pmatrix} &22\ &-6\ &-26\ &17\ \\ &-17\ &5\ &20\ &-13\ \\ &-1\ &0\ &2\ &-1\ \\ &4\ &-1\ &-5\ &3\ \end{pmatrix}\end{aligned}$$

你的问题在这里没有得到解决?请到 热门难题 里面看看吧!


Elementary transformations of matrices:


Definition:Applying the following three transformations to the rows (columns) of a matrix becomes the elementary transformation of the matrix
(1) Swap the positions of two rows (columns) in a matrix;
(2) Using non-zero constants λ Multiply a certain row (column) of a matrix;
(3) Convert a row (column) of a matrix γ Multiply to another row (column) of the matrix.



  New addition:Lenders ToolBox module(Specific location:Math OP > Lenders ToolBox ),welcome。