Mathematics
         
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Get the inverse matrix:
    Enter an invertible matrix, with each element separated by a comma and each row ending with a semicolon.
    Note that mathematical functions and variables are not supported.
    Current location:Linear algebra >Inverse matrix >History of inverse matrices >Answer

$$\begin{aligned}&\\ \color{black}{Calcu}&\color{black}{late\ the\ inverse\ matrix\ of\ } \ \ \begin{pmatrix} &2\ &1\ &3\ &4\ \\ &4\ &3\ &1\ &2\ \\ &1\ &3\ &4\ &2\ \\ &2\ &4\ &3\ &1\ \end{pmatrix}\color{black}{\ .}\\ \\Solu&tion:\\ &\begin{pmatrix} &2\ &1\ &3\ &4\ \\ &4\ &3\ &1\ &2\ \\ &1\ &3\ &4\ &2\ \\ &2\ &4\ &3\ &1\ \end{pmatrix}\\\\&\color{grey}{Using\ the\ elementary\ transformation\ of\ the\ matrix\ to\ find\ the\ inverse\ matrix:}\\&\left (\begin{array} {ccccc | cccc} &2\ &1\ &3\ &4\ &1\ &0\ &0\ &0\ \\ &4\ &3\ &1\ &2\ &0\ &1\ &0\ &0\ \\ &1\ &3\ &4\ &2\ &0\ &0\ &1\ &0\ \\ &2\ &4\ &3\ &1\ &0\ &0\ &0\ &1\ \\\end{array} \right )\\\\&\color{grey}{Transfprming\ a\ known\ matrix\ into\ an\ upper\ triangular\ matrix :}\\\\->\ \ &\left (\begin{array} {ccccc | cccc} &2\ &1\ &3\ &4\ &1\ &0\ &0\ &0\ \\ &0\ &1\ &-5\ &-6\ &-2\ &1\ &0\ &0\ \\ &0\ &\frac{5}{2}\ &\frac{5}{2}\ &0\ &-\frac{1}{2}\ &0\ &1\ &0\ \\ &0\ &3\ &0\ &-3\ &-1\ &0\ &0\ &1\ \\\end{array} \right )\\\\->\ \ &\left (\begin{array} {ccccc | cccc} &2\ &1\ &3\ &4\ &1\ &0\ &0\ &0\ \\ &0\ &1\ &-5\ &-6\ &-2\ &1\ &0\ &0\ \\ &0\ &0\ &15\ &15\ &\frac{9}{2}\ &-\frac{5}{2}\ &1\ &0\ \\ &0\ &0\ &15\ &15\ &5\ &-3\ &0\ &1\ \\\end{array} \right )\\\\->\ \ &\left (\begin{array} {ccccc | cccc} &2\ &1\ &3\ &4\ &1\ &0\ &0\ &0\ \\ &0\ &1\ &-5\ &-6\ &-2\ &1\ &0\ &0\ \\ &0\ &0\ &15\ &15\ &\frac{9}{2}\ &-\frac{5}{2}\ &1\ &0\ \\ &0\ &0\ &0\ &0\ &\frac{1}{2}\ &-\frac{1}{2}\ &-1\ &1\ \\\end{array} \right )\\\ \ &\color{red}{This\ matrix\ is\ an\ irreversible\ matrix.}\end{aligned}$$

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Elementary transformations of matrices:


Definition:Applying the following three transformations to the rows (columns) of a matrix becomes the elementary transformation of the matrix
(1) Swap the positions of two rows (columns) in a matrix;
(2) Using non-zero constants λ Multiply a certain row (column) of a matrix;
(3) Convert a row (column) of a matrix γ Multiply to another row (column) of the matrix.



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