detailed information: The input equation set is: Question solving process:
Multiply both sides of equation (1) by 2 Divide the two sides of equation (1) by 5, the equation can be obtained: | | 6 | A | | - | 12 5 | B | | - | 12 5 | C | + | | | 12 5 | D | = | | | 12 5 | (6) | , then add the two sides of equation (6) to both sides of equation (2), the equations are reduced to:
 | | | | | | 28 5 | B | | - | 12 5 | C | + | | | 7 5 | D | = | | - | 18 5 | | (2) |
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Multiply both sides of equation (1) by 2 Divide the two sides of equation (1) by 5, the equation can be obtained: | | 6 | A | | - | 12 5 | B | | - | 12 5 | C | + | | | 12 5 | D | = | | | 12 5 | (7) | , then add the two sides of equation (7) to both sides of equation (3), the equations are reduced to:
 | | | | | | 28 5 | B | | - | 12 5 | C | + | | | 7 5 | D | = | | - | 18 5 | | (2) |
| - | 12 5 | B | + | | | 28 5 | C | | - | 13 5 | D | = | | | 12 5 | | (3) |
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Divide the two sides of equation (1) by 15, the equation can be obtained: | | A | | - | 2 5 | B | | - | 2 5 | C | + | | | 2 5 | D | = | | | 2 5 | (8) | , then subtract both sides of equation (8) from both sides of equation (5), the equations are reduced to:
 | | | | | | 28 5 | B | | - | 12 5 | C | + | | | 7 5 | D | = | | - | 18 5 | | (2) |
| - | 12 5 | B | + | | | 28 5 | C | | - | 13 5 | D | = | | | 12 5 | | (3) |
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Multiply both sides of equation (2) by 3 Divide the two sides of equation (2) by 7, the equation can be obtained: | | | 12 5 | B | | - | 36 35 | C | + | | | 3 5 | D | = | | - | 54 35 | (9) | , then add the two sides of equation (9) to both sides of equation (3), the equations are reduced to:
 | | | | | | 28 5 | B | | - | 12 5 | C | + | | | 7 5 | D | = | | - | 18 5 | | (2) |
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Multiply both sides of equation (2) by 5 Divide the two sides of equation (2) by 28, the equation can be obtained: | | B | | - | 3 7 | C | + | | | 1 4 | D | = | | - | 9 14 | (10) | , then subtract both sides of equation (10) from both sides of equation (4), the equations are reduced to:
 | | | | | | 28 5 | B | | - | 12 5 | C | + | | | 7 5 | D | = | | - | 18 5 | | (2) |
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Divide the two sides of equation (2) by 14, the equation can be obtained: | | | 2 5 | B | | - | 6 35 | C | + | | | 1 10 | D | = | | - | 9 35 | (11) | , then subtract both sides of equation (11) from both sides of equation (5), the equations are reduced to:
 | | | | | | 28 5 | B | | - | 12 5 | C | + | | | 7 5 | D | = | | - | 18 5 | | (2) |
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Divide the two sides of equation (3) by 8, the equation can be obtained: , then add the two sides of equation (12) to both sides of equation (4), the equations are reduced to:
 | | | | | | 28 5 | B | | - | 12 5 | C | + | | | 7 5 | D | = | | - | 18 5 | | (2) |
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Divide the two sides of equation (3) by 8, the equation can be obtained: , then subtract both sides of equation (13) from both sides of equation (5), the equations are reduced to:
 | | | | | | 28 5 | B | | - | 12 5 | C | + | | | 7 5 | D | = | | - | 18 5 | | (2) |
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Divide the two sides of equation (4) by 2, the equation can be obtained: , then subtract both sides of equation (14) from both sides of equation (5), the equations are reduced to:
 | | | | | | 28 5 | B | | - | 12 5 | C | + | | | 7 5 | D | = | | - | 18 5 | | (2) |
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由第(5)方程式可以看出,该方程组无解。
解方程组的详细方法请参阅:《多元一次方程组的解法》 |