detailed information: The input equation set is:
 | | | | A | + | | B | | -1 | D | | -1 | E | | -1 | F | = | | 0 | | (1) |
| | | | | | Question solving process:
Subtract both sides of equation (1) from both sides of equation (2) ,the equations are reduced to:
 | | | | A | + | | B | | -1 | D | | -1 | E | | -1 | F | = | | 0 | | (1) |
| -2 | B | | -1 | C | + | | D | + | | E | + | | F | = | | 2 | | (2) |
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Subtract both sides of equation (1) from both sides of equation (5) ,the equations are reduced to:
 | | | | A | + | | B | | -1 | D | | -1 | E | | -1 | F | = | | 0 | | (1) |
| -2 | B | | -1 | C | + | | D | + | | E | + | | F | = | | 2 | | (2) |
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Divide the two sides of equation (2) by 2, the equation can be obtained: | -1 | B | | - | 1 2 | C | + | | | 1 2 | D | + | | | 1 2 | E | + | | | 1 2 | F | = | | 1 | (7) | , then subtract both sides of equation (7) from both sides of equation (5), the equations are reduced to:
 | | | | A | + | | B | | -1 | D | | -1 | E | | -1 | F | = | | 0 | | (1) |
| -2 | B | | -1 | C | + | | D | + | | E | + | | F | = | | 2 | | (2) |
| | | | | 3 2 | C | + | | | 1 2 | D | + | | | 1 2 | E | | - | 1 2 | F | = | | -1 | | (5) |
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Divide the two sides of equation (2) by 2, the equation can be obtained: | -1 | B | | - | 1 2 | C | + | | | 1 2 | D | + | | | 1 2 | E | + | | | 1 2 | F | = | | 1 | (8) | , then add the two sides of equation (8) to both sides of equation (6), the equations are reduced to:
 | | | | A | + | | B | | -1 | D | | -1 | E | | -1 | F | = | | 0 | | (1) |
| -2 | B | | -1 | C | + | | D | + | | E | + | | F | = | | 2 | | (2) |
| | | | | 3 2 | C | + | | | 1 2 | D | + | | | 1 2 | E | | - | 1 2 | F | = | | -1 | | (5) |
| - | 3 2 | C | | - | 1 2 | D | | - | 1 2 | E | + | | | 1 2 | F | = | | 1 | | (6) |
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交After the exchange of equation (3) and equation (4), the equation system becomes:
 | | | | A | + | | B | | -1 | D | | -1 | E | | -1 | F | = | | 0 | | (1) |
| -2 | B | | -1 | C | + | | D | + | | E | + | | F | = | | 2 | | (2) |
| | | | | 3 2 | C | + | | | 1 2 | D | + | | | 1 2 | E | | - | 1 2 | F | = | | -1 | | (5) |
| - | 3 2 | C | | - | 1 2 | D | | - | 1 2 | E | + | | | 1 2 | F | = | | 1 | | (6) |
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Multiply both sides of equation (3) by 3 Divide the two sides of equation (3) by 2, the equation can be obtained: | - | 3 2 | C | + | | 3 | E | | - | 3 2 | F | = | | | 15 2 | (9) | , then add the two sides of equation (9) to both sides of equation (5), the equations are reduced to:
 | | | | A | + | | B | | -1 | D | | -1 | E | | -1 | F | = | | 0 | | (1) |
| -2 | B | | -1 | C | + | | D | + | | E | + | | F | = | | 2 | | (2) |
| | | | - | 3 2 | C | | - | 1 2 | D | | - | 1 2 | E | + | | | 1 2 | F | = | | 1 | | (6) |
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Multiply both sides of equation (3) by 3 Divide the two sides of equation (3) by 2, the equation can be obtained: | - | 3 2 | C | + | | 3 | E | | - | 3 2 | F | = | | | 15 2 | (10) | , then subtract both sides of equation (10) from both sides of equation (6), the equations are reduced to:
 | | | | A | + | | B | | -1 | D | | -1 | E | | -1 | F | = | | 0 | | (1) |
| -2 | B | | -1 | C | + | | D | + | | E | + | | F | = | | 2 | | (2) |
| | | | - | 1 2 | D | | - | 7 2 | E | + | | 2 | F | = | | - | 13 2 | | (6) |
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Divide the two sides of equation (4) by 2, the equation can be obtained: , then subtract both sides of equation (11) from both sides of equation (5), the equations are reduced to:
 | | | | A | + | | B | | -1 | D | | -1 | E | | -1 | F | = | | 0 | | (1) |
| -2 | B | | -1 | C | + | | D | + | | E | + | | F | = | | 2 | | (2) |
| | | | - | 1 2 | D | | - | 7 2 | E | + | | 2 | F | = | | - | 13 2 | | (6) |
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Divide the two sides of equation (4) by 2, the equation can be obtained: , then add the two sides of equation (12) to both sides of equation (6), the equations are reduced to:
 | | | | A | + | | B | | -1 | D | | -1 | E | | -1 | F | = | | 0 | | (1) |
| -2 | B | | -1 | C | + | | D | + | | E | + | | F | = | | 2 | | (2) |
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Add both sides of equation (5) to both sides of equation (6) ,the equations are reduced to:
 | | | | A | + | | B | | -1 | D | | -1 | E | | -1 | F | = | | 0 | | (1) |
| -2 | B | | -1 | C | + | | D | + | | E | + | | F | = | | 2 | | (2) |
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Divide both sides of equation (5) by 4, get the equation:, then add the two sides of equation (13) to both sides of equation (4), get the equation:
 | | | | A | + | | B | | -1 | D | | -1 | E | | -1 | F | = | | 0 | | (1) |
| -2 | B | | -1 | C | + | | D | + | | E | + | | F | = | | 2 | | (2) |
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Divide both sides of equation (5) by 2, get the equation:, then subtract both sides of equation (14) from both sides of equation (3), get the equation:
 | | | | A | + | | B | | -1 | D | | -1 | E | | -1 | F | = | | 0 | | (1) |
| -2 | B | | -1 | C | + | | D | + | | E | + | | F | = | | 2 | | (2) |
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Divide both sides of equation (5) by 4, get the equation:, then subtract both sides of equation (15) from both sides of equation (2), get the equation:
 | | | | A | + | | B | | -1 | D | | -1 | E | | -1 | F | = | | 0 | | (1) |
| -2 | B | | -1 | C | + | | D | + | | | 3 2 | F | = | | | 5 8 | | (2) |
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Divide both sides of equation (5) by 4, get the equation:, then add the two sides of equation (16) to both sides of equation (1), get the equation:
 | | | | A | + | | B | | -1 | D | | - | 3 2 | F | = | | | 11 8 | | (1) |
| -2 | B | | -1 | C | + | | D | + | | | 3 2 | F | = | | | 5 8 | | (2) |
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Subtract both sides of equation (4) from both sides of equation (2), get the equation:
 | | | | A | + | | B | | -1 | D | | - | 3 2 | F | = | | | 11 8 | | (1) |
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Add both sides of equation (4) to both sides of equation (1), get the equation:
Subtract both sides of equation (3) from both sides of equation (2), get the equation:
Divide both sides of equation (2) by 2, get the equation:, then add the two sides of equation (17) to both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
Where: F are arbitrary constants. 解方程组的详细方法请参阅:《多元一次方程组的解法》 |