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On line solution of multivariate equations：
    First set the elements of the equation (i.e. the number of unknowns), then click the "Next" button to enter the coefficients of each element of the equation set, and click the "Next" button to obtain the solution of the equation set.
    Note that the coefficients of each element of the equation system can only be numbers, not algebraic expressions (including mathematical functions).
    Current location：Equations > Multivariate equations > Answer
detailed information：
The input equation set is:
 2A -5B = 2    (1)
-5A + 6C = 0    (2)
-4A + 12D = 0    (3)
- 
1
4
A + 
239
4
B - 
1
4
C - 
1
4
D = 
216
5
    (4)
Question solving process:

Multiply both sides of equation (1) by 5
Divide the two sides of equation (1) by 2, the equation can be obtained:
         5A - 
25
2
B = 5    (5)
, then add the two sides of equation (5) to both sides of equation (2), the equations are reduced to:
 2A -5B = 2    (1)
- 
25
2
B + 6C = 5    (2)
-4A + 12D = 0    (3)
- 
1
4
A + 
239
4
B - 
1
4
C - 
1
4
D = 
216
5
    (4)

Multiply both sides of equation (1) by 2, the equation can be obtained:
         4A -10B = 4    (6)
, then add the two sides of equation (6) to both sides of equation (3), the equations are reduced to:
 2A -5B = 2    (1)
- 
25
2
B + 6C = 5    (2)
-10B + 12D = 4    (3)
- 
1
4
A + 
239
4
B - 
1
4
C - 
1
4
D = 
216
5
    (4)

Divide the two sides of equation (1) by 8, the equation can be obtained:
         
1
4
A - 
5
8
B = 
1
4
    (7)
, then add the two sides of equation (7) to both sides of equation (4), the equations are reduced to:
 2A -5B = 2    (1)
- 
25
2
B + 6C = 5    (2)
-10B + 12D = 4    (3)
 
473
8
B - 
1
4
C - 
1
4
D = 
869
20
    (4)

Multiply both sides of equation (2) by 4
Divide the two sides of equation (2) by 5, the equation can be obtained:
        -10B + 
24
5
C = 4    (8)
, then subtract both sides of equation (8) from both sides of equation (3), the equations are reduced to:
 2A -5B = 2    (1)
- 
25
2
B + 6C = 5    (2)
- 
24
5
C + 12D = 0    (3)
 
473
8
B - 
1
4
C - 
1
4
D = 
869
20
    (4)

Multiply both sides of equation (2) by 473
Divide the two sides of equation (2) by 100, the equation can be obtained:
        - 
473
8
B + 
1419
50
C = 
473
20
    (9)
, then add the two sides of equation (9) to both sides of equation (4), the equations are reduced to:
 2A -5B = 2    (1)
- 
25
2
B + 6C = 5    (2)
- 
24
5
C + 12D = 0    (3)
 
2813
100
C - 
1
4
D = 
671
10
    (4)

Multiply both sides of equation (3) by 2813
Divide the two sides of equation (3) by 480, the equation can be obtained:
        - 
2813
100
C + 
2813
40
D = 0    (10)
, then add the two sides of equation (10) to both sides of equation (4), the equations are reduced to:
 2A -5B = 2    (1)
- 
25
2
B + 6C = 5    (2)
- 
24
5
C + 12D = 0    (3)
 
2803
40
D = 
671
10
    (4)

Multiply both sides of equation (4) by 480
Divide both sides of equation (4) by 2803, get the equation：
         
33636
2803
D = 
32208
2803
    (11)
, then subtract both sides of equation (11) from both sides of equation (3), get the equation：
 2A -5B = 2    (1)
- 
25
2
B + 6C = 5    (2)
- 
24
5
C = - 
32208
2803
    (3)
 
2803
40
D = 
671
10
    (4)

Multiply both sides of equation (3) by 5
Divide both sides of equation (3) by 4, get the equation：
        -6C = - 
40260
2803
    (12)
, then add the two sides of equation (12) to both sides of equation (2), get the equation：
 2A -5B = 2    (1)
- 
25
2
B = - 
26245
2803
    (2)
- 
24
5
C = - 
32208
2803
    (3)
 D = 
2684
2803
    (4)

Multiply both sides of equation (2) by 2
Divide both sides of equation (2) by 5, get the equation：
        -5B = - 
10498
2803
    (13)
, then subtract both sides of equation (13) from both sides of equation (1), get the equation：
 2A = 
16104
2803
    (1)
- 
25
2
B = - 
26245
2803
    (2)
 C = 
6710
2803
    (3)
 D = 
2684
2803
    (4)

The coefficient of the unknown number is reduced to 1, and the equations are reduced to：
 A = 
8052
2803
    (1)
 B = 
10498
14015
    (2)
 C = 
6710
2803
    (3)
 D = 
2684
2803
    (4)


Therefore, the solution of the equation set is:
A = 
8052
2803
B = 
10498
14015
C = 
6710
2803
D = 
2684
2803


Convert the solution of the equation set to decimals:
A = 2.872636
B = 0.749055
C = 2.393864
D = 0.957545

解方程组的详细方法请参阅：《多元一次方程组的解法》
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